| Mathematics - 1801 - 610 pages
...2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply the sum of the two **parallel sides by the perpendicular distance between them, and half the product will be the area.** • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A ABD+ A BCD, or , , , ABxDE , DCxDE the... | |
| James Thompson - Arithmetic - 1808 - 172 pages
...IV. To find the area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. **RULE — Multiply the sum of the parallel sides by...between them, and half the product •will be the area.** EXAMPLES. 13. Required the area of a trapezoid whose parallel sidef »re 25 feel 6 inches, and 18 feet... | |
| Peter Nicholson - 1809
...BF. 14 X36 84 42 504=the area of ABCD. PROBLEM VI. To find the area of a trapezoid. Multiply the half **sum of the parallel sides by the perpendicular distance between them, and** the product will be the area. EXAMPLE I. What is fhe area of a board or plank in the form of a trapeziod,... | |
| Matthew Iley - 1820
...Area of a Quadrilateral wherein two unequal Sides are Parallel to one another. RULE. Multiply half **the sum of the parallel sides by the perpendicular distance between them, and** the product will be the area. Let ABCD be a quadrilateral, wherein AC and BD are parallel but unequal;... | |
| Anthony Nesbit, W. Little - Gaging - 1822 - 533 pages
...bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply the sum of the two **parallel sides by the perpendicular distance between them, and half the product will be the area** in square inches. Divide this area by 2 82, 231, and 2150.42, and the respective quotients will be... | |
| John Nicholson - Machinery - 1825 - 795 pages
...been subtracted. 63 I 189 3 1 189 Prot. 4. To find the Area ofaTrapezoid. Multiply the sum of the two **parallel sides by the perpendicular distance between them, and half the product will be the area.** Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and the perpendicular distance AP or CN... | |
| Peter Nicholson - Mathematics - 1825 - 372 pages
...42 501 = the arca of ABCD. MENSURATION. Prob. 6. To find the area of a trapezoid. Multiply the half **sum of the parallel sides by the perpendicular distance between them, and** the product will be the area. Ex. 3. What is the area of a board or plank in the form of a trapezoid,... | |
| Thomas Hornby - Surveying - 1827 - 270 pages
...• • 00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. **RULE. Multiply the sum of the parallel sides by the...between them, and half the product will be the area.** EXAMPLE. Required the area of the trapezoid AB CD, whose parallel sides AB and DC are 800 and 640 links... | |
| John Bonnycastle - Geometry - 1829 - 252 pages
...PROBLEM VI. To find the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. **RULE.* Multiply the sum of the parallel sides by the...distance between them, and half the product will be the** EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and DC are 321.51 and 214.24,... | |
| Edinburgh encyclopaedia - History - 1830
...trapezoid. Note. A trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. **RULE. Multiply the sum of the parallel sides by the...perpendicular distance between them, and half the product** is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities draw AE, CF at right... | |
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