| John Playfair - Trigonometry - 1806 - 311 pages
...is the same with the duplicate ratio of their sides ; and hence, also, any two similar rectilineal **figures are to each other as the squares of their homologous sides.** PROP. XXI. THEOR. Book VI. RECTILINEAL figures, which are similar to the same rectilineal figure, are... | |
| Thomas Keith, William Hawney - 1817
...I = 7- X VD — d 3/ \D — d 3/ a — d 3 the solidity of the frustum ABD c. Now all similar plane **figures are to each other as the squares of their homologous sides.** Therefore A 1 a : : D* : d* or — = — , put each off these equal to m ; then A — * D* and a —... | |
| Adrien Marie Legendre - Geometry - 1822 - 367 pages
...polygon, we shall have S' =p'2? : (A, B, A' B', &c.) Hence S : S': :p2 :p's ; hence the surfaces of **similar figures are to each other as the squares of their homologous sides.** Let us now proceed to polyedrons. We may take it for granted, that a face is determined by means of... | |
| Jeremiah Day, Matthew Rice Dutton - Geometry - 1824
...original figure. The area of the triangle may then be found by multiplying its base into half its height ; **and this will be the contents of the field. In practice...other as the squares of their homologous sides. (Euc.** 20.6.) The proportion may be stated thus ; As the square of the true chain, to the square of that by... | |
| Euclid, Dionysius Lardner - Euclid's Elements - 1828 - 324 pages
...polygon, we shall have S' = ^/i0 : (A, B, A', B', &c.) Hence S : S' : : p2 : p'1 ; hence the surfaces of **similar figures are to each other as the squares of their homologous sides.** Let us now proceed to polyedrons. We may take it for granted, that a face is determined by means of... | |
| Timothy Walker - Geometry - 1829 - 129 pages
...ABCDE:FGHIK::ABC:FGH. But ABC : FGH : : AB* : p G*. Therefore ABCDE : FGHIK : : AB* : FG*. In other words, **similar figures are to each other as the squares of their homologous sides.** 117. THEOREM. — Circles are to each other as the squares of their radii. No diagram is necessary... | |
| Francis Nichols - Mathematics - 1829 - 186 pages
...other is the same with the duplicate ratio of their sides; and hence, also, any two similar rectilineal **figures are to each other as the squares of their homologous sides.** CoR. 3. Two similar triangles, or two similar polygons, are to each other as any rectilineal figure... | |
| Jeremiah Day - Logarithms - 1831 - 155 pages
...original figure. The area of the triangle may then be found by multiplying its base into half its height ; **and this will be the contents of the field. In practice,...the area of a field measured by a chain 66.4 feet** long, be computed to be 32.6036 acres ; what is the area as measured by the true chain 66 feet long... | |
| Jeremiah Day - Measurement - 1831
...original figure. The area of the triangle may then be found by multiplying its base into half its height ; **and this will be the contents of the field. In practice,...the area of a field measured by a chain 66.4 feet** long, be computed to be 32.6036 acres ; what is the area as measured by the true chain 66 feet long... | |
| Arithmetic - 1831 - 396 pages
...the polygon ; then multiply that square by the multiplier set against the name *This rule depends on **the principle, that similar figures are to each other as the squares** oftluir llke sides. The multipllers in the table are the areas of the respective figures to the side... | |
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