Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain Practical System of Arithmetic, Adapted to the United States (Google eBook)

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Samuel Green, 1823 - Arithmetic - 240 pages
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Page 220 - To measure a parallelogram, or long square. RULE. Multiply the length by the breadth, and the product will be the area, or superficial content.
Page 150 - CASE I. When it is required to find how many of the first sort of coin, weight or measure, mentioned in the question^ are equal to a given quantity of the last.
Page ii - IDE, of the said District, hath deposited in this office, the title of a book, the right whereof he claims as proprietor, in the words following, to wit : " Inductive Grammar, designed for beginners. By an Instructer." In conformity to the act of the Congress of the United States...
Page 226 - Multiply the length by the breadth, and that product by the depth, divide the last product by 2150,425 the solid inches in a statute bushel, and the quotient will be tke answer. EXAMPLE. There is a square...
Page 100 - ... 3. Multiply the second and third terms together, and divide their product by the first term , the quotient will be the answer to the question, in the same denomination you left the, second term in, which may be brought into anv other denomination required.
Page 180 - ... subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. " Place the double of the root, already found, on the lefl hand of the dividend for a divisor. 4. " Seek how often the divisor is contained...
Page 138 - PAYMENTS, iS finding the equated time to pay at once, several debts due at different periods of time, so that no loss shall be sustained by either party. RULE. Multiply each payment by its time, and divide the sum of the several products by the whole debt, and the quotient will be the equated time" for the payment of the whole.
Page 108 - THE Rule of Three Inverse, teaches by having three numbers given to find a fourth, which shall have the same proportion to the second, as the first has to the third. If more requires more, or less requires less, the quel...
Page 159 - Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Page 161 - Reduce the given fraction to such a compound one, as will express the value of the given fraction, by comparing it with all the denominations between it and that denomination you would reduce it to ; lastly, reduce this compound fraction to a single one, by Case V.

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