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12 feet 12 inches 20 feet 9 feet ABCD assumed cube avoirdupois axis breadth centre chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface cube root cubic ft cubic inches cylinder cylindrical ring decimal Diff divide the product ellipse ends entire surface equal extract the square feet 1 OPERATION feet 6 inches feet long find the area find the Solidity frustrum gallon half Hyperbola hypotenuse inner diameter inscribed square lateral surface length miles multiply the sum Nonagon Note.—The number of sides number of square parabola parallelogram pentagonal pyramid perimeter perpendicular distance perpendicular height plane prism PROBLEM radius regular pentagonal regular Polygon Required the area Required the solidity rhombus right angled triangle rule Rule.—Find Rule.—I Rule.—Multiply sector slant height solid contents sphere spherical segment spheroid square feet square miles square rods square root square yards thickness trapezium zoid zone
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.