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acres added annex ciphers Answer arithmetic arithmetical series called cent column common denominator contains 18 cube cubic foot cubic inches decimal fraction decimal places decimal point divided dividend and divisor division equal example EXERCISES farthings fingers following rule four numbers given gives greater greatest common measure Hence hund hundreds IOO IOOO last article last terms least common multiple length less means merator method metical miles multiple-part multiplicand number of ciphers number of combinations number of decimal number of figures number of permutations number of terms number or fraction numerator and denominator obtained parallelopiped pebbles pence places of decimals pound proceed proportion pupil quantity question quotient reduced result shew shewn shillings sides specific gravity square number square root subtracted Suppose it required taken ten-thous tens thing third thousands twice whole number write
Page 33 - the following rule for the multiplication of algebraic quantities: Multiply each term of the multiplicand by each term of the multiplier; when the two terms
Page 105 - That is, the sum of the first and second is to the second, as the sum of the third and fourth is to the fourth.
Page 76 - by moving the decimal point as many places to the left as there are ciphers in the
Page 169 - Had there been a gain, A would have gained 4 times as much as B, and C as much as A and B together. How much of the loss must each bear?
Page vii - When the principle has been thus discussed, let the rule be distinctly stated by the master or some of the more intelligent of the pupils, and let some very simple example be worked at length. The pupils may then be dismissed, to try the more complicated exercises with which the work will furnish them, or any others which may be proposed.
Page 43 - as many figures* from the right of the dividend as there are ciphers at the right of the divisor.
Page 19 - a number from the first, if you subtract the same number from the second. Conceive two baskets with pebbles in them, in the first of which are 100 pebbles more than in the second. If I put 50 more pebbles into each of them, there are still only