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Books Books 1 - 10 of 21 on In like manner, we have, cos B . sin c = cos b . sin A— sin B . cos c . cos a.....  
" In like manner, we have, cos B . sin c = cos b . sin A— sin B . cos c . cos a. Exterminating cos b from these, there results cos A = cos a . sin B sin c —cos B . cos c. "
Elements of analytic trigonometry, plane and spherical - Page 139
by Ferdinand Rudolph Hassler - 1826
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Réciproques de la géométrie: suivies d'un recueil de théorèmes et de problèmes

Jean-Guillaume Garnier - Geometry - 1810 - 348 pages
...sin C = cos b sin A — sin B cos C cos a.... (6) .1 Eliminant cos b entre (5) et (6), on obtiendra cos A = cos a sin B sin C — cos B cos C et de même cos B = cos b sin A sin C — cos A «os C cos C = cos c sin A sin B — cos A cos B qui...
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Réciproques de la géométrie: suivies d'un recueil de théorèmes et de problèmes

Jean Guillaume Garnier - Geometry - 1810 - 348 pages
...sin C = cos b sin A — sin B cos C cos a. . . .(6) ,\ Eliminant cos b entre (5) et (6), on obtiendra cos A = cos a sin B sin C — cos B cos C\ et de même f > (3,); cos B = cos b sin A sin C — cos A cos Cl cos C = cos c sin A sin B — cos...
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A course of mathematics: in three volumes : composed for the use of the ...

Charles Hutton - Mathematics - 1811
...cos B . sin c = cos b . sin A — sots . cos c . cos a. Exterminating cos b from these, there results cos A = cos a . sin B . sin c — cos B . cos c. "1 So like- 1 cos B = cos b . sin A . sin c — cos A. . cos c. f (IV.) wise 5 cos c == cos c ' s'n...
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Élémens de géométrie: comprenant les deux trigonométries, une introduction á ...

Jean Guillaume Garnier - Geometry - 1812 - 311 pages
...C = cos. b sin. A — sin. B cos. C cos. a... (6,V Eliminant cos. b entre (5) et (6) , on obtiendra cos. A = cos. a sin. B sin. C — cos. B cos. C et de même . , „ f •.. (y) cos. B = cos. b sin. A sin. C — cos. A cos. C ' cos. C = cos. c sin....
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A Course of Mathematics ...: For the Use of Academies, as Well as ..., Volume 2

Charles Hutton - Mathematics - 1812
...cos B . sin c = cos b . sin A— sin B . cos c . cos a. Exterminating cos b from these, there results cos A = cos a . sin B sin c —cos B . cos c. 1 So like- 7 cos B = cos b . sin A sin c — cos A .'cos c. > (IV.) wise J cos c = cos c . sin A sin...
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Memoires, Volume 4

Societe des Sciences Physiques et Naturelles de Bordeaux - Science - 1866
...Asinfr — sinBsina, cosa = cos&cosc -+- sin b sine cos A, col A sin C -i- cosCcosô — sinbcoln, cos A — cos a sin B sin C — cos B cos C. EXTRAIT DE LA CORRESPONDANCE DE GAUSS ET DE SCHUMACHER. SCHUMACHER A GAUSS. Je prends la liberté de...
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Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Olinthus Gregory - Plane trigonometry - 1816 - 244 pages
...respectively opposite a, b, c, the sides b and c were constant. Then, from equa. (2) chap. vi. we have cos a = cos A sin b sin c + cos b cos c, This becomes by differentiation, — i'a sin a = — J'A sin A sin b sin c. The formula has only two...
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Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Olinthus Gregory - Plane trigonometry - 1816 - 244 pages
...B' sin c' cos a'. Here again we have three symmetrical equations applying to any spherical triangle, viz. cos A = cos a sin B sin c — cos B cos c"1 cos B = cos b sin A sin c — cos A cos c > (3. ) cos c = cos c sin A sin B — cos A cos BJ 23....
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A Course of Mathematics: For the Use of Academies, as Well as Private ...

Charles Hutton - Mathematics - 1822
...B . sin c == cos b , sin A — sin B . cos c . cos a. Exterminating cos b from these, there results cos A = cos a . sin B sin c — cos B . cos c. ) So like- } cos B = cos ft . sin A sin c—, cos A , cos c. \ (IV.) wise 5 cos c — cos c . sin A...
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Outlines of Natural Philosophy: Being the Heads of a Course of ..., Volumes 1-2

James Renwick - Physics - 1822
...C cot A > C cos c cos A = cot 6 sin c — sin A cot BJ eos C = cos c sin A sin B — cos A cos B '\ cos A = cos a sin B sin C — cos B cos C > D cos B = cos c sin C sin A — cos C cos A j These formulae are not well adapted to calculations,...
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