| Robert Edouard Moritz - Mathematics - 1913 - 453 pages
...the product of the tangents of the adjacent parts, and the five on the left are contained in Rule 2. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. These two rules are known as Napier,s Rules of the Circular Parts. 17.... | |
| George Neander Bauer, William Ellsworth Brooke - Trigonometry - 1917 - 313 pages
...follows : The sine of the middle part is equal to the product of the cosines of the opposite parts. **The sine of the middle part is equal to the product of the tangents of the** adjacent parts.* * To associate cosine with opposite and tangent with adjacent, it may be noticed that... | |
| George Neander Bauer, William Ellsworth Brooke - Textbooks - 1917 - 313 pages
...middle part and со с and со ß are opposite parts. Napier's rules may now be stated as follows : **The sine of the middle part is equal to the product of the** cosines of the opposite parts. Tlie sine of the middle part is equal to the product of the tangents... | |
| Smithsonian Institution, Richard Lionel Hippisley - Elliptic functions - 1922 - 314 pages
...omitted. The sine of the middle part is equal to the product of the tangents of the adjacent parts. **The sine of the middle part is equal to the product of the** cosines of opposite parts. From these rules the following equations follow: sin a = sin с sin a, tan... | |
| James Atkins Bullard, Arthur Kiernan - Plane trigonometry - 1922 - 230 pages
...sine of a middle part is equal to the product of the cosines of the opposite parts. 2. The sine of a **middle part is equal to the product of the tangents of the** adjacent parts. (61) The parts mentioned in the rules are the five so-called circular parts of the... | |
| Howard Whitley Eves - Mathematics - 1983 - 270 pages
...any middle part is equal to the product of the cosines of the two opposite parts. 2. The sine of any **middle part is equal to the product of the tangents of the two adjacent parts.** (a) By applying each of the above rules to each of the circular parts, obtain the ten formulas used... | |
| Daniel Zwillinger - Mathematics - 2002 - 928 pages
...above for a right spherical triangle may be recalled by the following two rules: 1 . The sine of any **middle part is equal to the product of the tangents of the two adjacent parts.** 2. The sine of any middle part is equal to the product of the cosines of the two opposite parts. 4.19.1.2... | |
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