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Books Books 11 - 20 of 134 on Then multiply the second and third terms together, and divide the product by the....  
" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
Mathematical Dictionary and Cyclopedia of Mathematical Science: Comprising ... - Page 86
by Charles Davies - 1872
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A Treatise of Practical Arithmetic

1819
...we have the equation ad = be, and this divided by a, will give d = . In words multiply the a second and third terms together, and divide the product by the first, and the quotient will be the fourth, or term required. II. IN ALLIGATION ALTERNATE. Let a, A, = the...
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The Scholar's Arithmetic: Designed for the Use of Schools in the United States

Jacob Willetts - Arithmetic - 1822 - 191 pages
...DIRECT PROPORTION. RULE. Prepare the given terms, if necessary, and state them as ia whole numbers : multiply the second and third terms together, and divide the product by the first : Or, Invert the first term and multiply the three together, as in Multiplication. EXAMPLES. i . If...
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The teachers' assistant: or a system of practical arithmetic

Arithmetic - 1824 - 198 pages
...THREE, IN VULGAR FRACTIONS. Prepare the given terms, if necessary, and state them as in whole numbers ; multiply the second and third terms together, and divide the product by the first. Or, Invert the dividing term, and multiply the three terms together, as in Multiplication. EXAMPLES....
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The American tutor's assistant, revised: or, A compendious system of ...

Zachariah Jess, Charles Hutton - Arithmetic - 1824 - 210 pages
...dols. ' A " 5 ' 3 : 6 :: 9 : 1 8 more requiring more I 20 : 40 :: 3 : 10 less requiring less RULE. Multiply the second and third terms together, and divide the product by the first ; the quotient will be the fourth term, or answer ; in the same name with the second. PROOF. Invert...
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The New Federal Calculator: Or Scholar's Assistant : Containing the Most ...

Thomas Tucker Smiley - Arithmetic - 1825 - 180 pages
...second terms to the same denomination, and to the lowest denomination mentioned in either oi them. 3. Multiply the second and third terms together, and divide the product by the first term; the result will be-tbe fourth term OF answer in the same denomination to which the third term was reduced....
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Temple's arithmetick: A concise introduction to practical arithmetick: in ...

Samuel Temple - Arithmetic - 1825 - 107 pages
...mentioned. Having properly stated the question, multiply the second and third terms into each other, and divide the product by the first term ; the quotient will be the answer, or number, sought. JVo/e 3. The answer always come: in the same denomination with the middle...
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Pike's System of Arithmetic Abridged: To which are Added Appropriate ...

Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 200 pages
...kind, the first term ; and that which is of the same name or kind with the answer, the second term. 2. Multiply the second and third terms together, and divide the product by the first term, and the quotient will be the fourth term, or answer. The notes under the general rule are applicable...
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Syllabus of Philosophical Lectures Given During Each Half Year at Popular ...

Poplar House Academy, London, J & S. - 1826 - 92 pages
...when necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then, multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ;...
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The Youth's Assistant in Theoretick and Practical Arithmetick ...

Zadock Thompson - Arithmetic - 1826 - 164 pages
...the same kind, the first term, and that which is of the same kind as the answer, the second term. 2.f Multiply the second and third terms together, and divide the product by the first, the quotient will be the answer. EXAMPLE. If 8lb. of sugar cost $1.00, what will 401b-. of sugar...
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The improved arithmetic: newly arranged and clearly illustrated, both ...

Arithmetic - 1828 - 339 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination...
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