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" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
Mathematical Dictionary and Cyclopedia of Mathematical Science: Comprising ... - Page 86
by Charles Davies - 1872 - 592 pages
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Adams's new arithmetic: Arithmetic, in which the principles of operating by ...

Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first...
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Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first...
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The Federal Calculator; Or, Scholar's Assistant : Containing the Most ...

Thomas Tucker Smiley - 1830 - 180 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. Multiply the second and third terms together, and divide the product by the .first term ; the result will be the fourth term, or answer, in the same denomination to which the third term was reduced....
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Adams's New arithmetic: Arithmetic, in which the principles of operating by ...

Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first...
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Adams's New Arithmetic

Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first...
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The teacher's assistant: or, A system of practical arithmetic: wherein the ...

Arithmetic - 1831 - 198 pages
...are; and if the third term consist of several denominations, reduce it to its lowest denomination; then, Multiply the second and third terms together,...product by the first term: the quotient will be the answer. Note. — The product of the second and third termsis of the same denomination as the third...
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Adam's new arithmetic: Arithmetic, in which the principles of operating by ...

Daniel Adams - Arithmetic - 1831 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination cs the third term. Note 1. If the first...
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Conkling's Arithmetic: The Young Arithmetician's Guide to a Knowledge of ...

Thomas Conkling (W.) - Arithmetic - 1831 - 275 pages
...before taught; then, state the question as directed in whole numbers, p. 109; and, as in that rule, multiply the second and third terms together, and divide the product by the first; that is, multiply the denominator of the first term by the numerators of the 2d and 3d, for a new numerator;...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - Surveying - 1832 - 348 pages
...may be as much greater or less than the third as the second term is greater or less than the first, then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer ; — in the same denomination with the third term. EXAMPLES. If...
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Encyclopædia americana, Volume 11

Francis Lieber, Edward Wigglesworth, Thomas Gamaliel Bradford, Henry Vethake - Reference - 1832
...less, place the greater of these two terms on the left, and the less in the middle ; and in bom cases, multiply the second and third terms together, and divide the product by the first term for the answer, which will always be of the same denomination as the third term. — Note 1. If the...
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