# A concise system of arithmetic: peculiarly adapted to the use of schools, in two parts. contains-the several rules, with a variety of examples under each. contains-answers to the examples in part I, together with the principal steps of the more tedious operations ..., Parts 1-2

Printed by G. Caw for J. Young, 1795 - Mathematics - 128 pages

### What people are saying -Write a review

We haven't found any reviews in the usual places.

### Contents

 Section 1 20 Section 2 33 Section 3 35 Section 4 47 Section 5 48 Section 6 67 Section 7 71 Section 8 96
 Section 10 101 Section 11 107 Section 12 110 Section 13 113 Section 14 114 Section 15 121 Section 16 123 Section 17 124

### Popular passages

Page 85 - If the errors are alike, divide the difference of the products by the difference of the errors, and the quotient will be the answer.
Page 78 - ... and place it on the left for a trial divisor. Find how many times the divisor is contained in the dividend, exclusive of the right hand figure, and place the quotient in the root and also on the right of the divisor. 4. Multiply the divisor thus increased, by the last ^figure of the root; subtract the product from the dividend ; to the remainder annex the next period for a new dividend. 5. Double the whole root found for a NEW trial divisor, and continue the operation as before, until all the...
Page 75 - Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend.
Page 78 - Subtract the square of this figure from the left-hand period, and to the remainder annex the next period for a dividend.
Page 40 - To reduce a compound fraction to an equivalent single one. RULE. — Multiply all the numerators together for the numerator, and all the denominators together for the denominator, and they will form the fraction required.
Page 7 - If any partial dividend will not contain the divisor, write a cipher in the quotient, then annex the next figure of the dividend and proceed as before.
Page 79 - ... is, The first term of an increasing arithmetical series is equal to the last term diminished by the product of the common difference into the number of terms less one. From the same formula, we find d= - T : that is. n — 1' In any arithmetical series, the common difference is.
Page 78 - ... the right. 2. Find the greatest cube number, in the left-hand period, and place the root of that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide the dividend by it, and put the quotient figure for the next figure of the root. 4. Multiply the part of the root formerly found by the last figure placed...
Page 43 - Reduce the fractions to common denominators, as in addition. Find the difference of the numerators, under which write the common denominator. From t\$ take f . Here the fractions are first 12X 7= 84? brought to a common denomina- 4X15= 60 J numcratoĞ tor ; then the 6O taken from 84, i5x~T=i05"com.
Page 40 - ... DENOMINATORS. When two or more fractions have the same number for a denominator, this number is called their Common Denominator. Fractions having different denominators, must be reduced to a common denominator, before addition or subtraction can be performed on them. RULE FOR REDUCING FRACTIONS TO A COMMON DENOMINATOR. Multiply each numerator into all tht denominators except its own, for a new numerator. Then multiply all the denominators together for a common denominator, and place it under...