Advanced Theory of Electricity and Magnetism: A Text-book for Colleges and Technical Schools

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Macmillan, 1915 - Electricity - 300 pages
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Page 17 - ... the product of the mass of the body into the square of the distance between the parallel axes.
Page 74 - ... of a dynamo has 5,000 turns of wire and, when a current of one ampere flows through the field winding, 1,500,000 lines of force are produced through the field core. Assuming that the flux is proportional to the exciting current, find the inductance of the field coil in henrys. Ans. 75 henrys. 112. A battery having an electromotive force of 10 volts and a resistance of one ohm is connected to a coil of wire wound on an iron core. The coil has 1,000 turns of wire and its resistance is 4 ohms. What...
Page 295 - Figure 171 represents a charged particle moving upwards through a magnetic field, the lines of force of which are perpendicular to the plane of the figure. The moving particle is equivalent to an electric current, and the side force F is equal to...
Page 118 - ... to AB. The component which is at right angles to AB has no perceptible magnetizing action on AB, the component which is parallel to AB causes the end B to become a north pole and the end A to become a south pole, and the magnetic field at C due to these magnet poles is parallel to BA and towards A. The magnetic field at the •compass box which is due to the temporary magnetism of the bar AB in Fig.
Page 254 - Fig. 175, energy will be transferred to the right (or left) by each horizontal chain of geared cells at a rate which is proportional to the product of the intensity of the magnetic field and the intensity of the electric field ; and the energy per second flowing across an area...
Page 82 - The ampere-turn. — The magnetomotive force along a path which links with one turn of wire carrying one ampere of current is called one ampere-turn. The magnetomotive force of any coil, in ampere-turns, is equal to the product of the current flowing in the coil in amperes multiplied by the number of turns of wire in the coil. In magnetic calculations it is usually convenient to reduce ampere-turns of magnetomotive force to cgs units (gilberts), which is done by multiplying ampere-turns by 47r/10,...
Page 2 - ... like magnetic poles repel each other, and unlike magnetic poles attract each other.
Page 254 - Fig. 1 74 to be rotating, positive cells in one direction, negative cells in the other, about axes perpendicular to the plane of the paper. This rotatory motion constitutes a magnetic field perpendicular to the plane of the paper and perpendicular to the electric field which is towards the bottom of the page. On account of the torque action between the cells, as explained in connection with Fig.
Page 261 - B will be relieved from the electrical stress. The explanation here given of the entire relief of the electrical stress between two plates by the establishment of a conducting line (line of slip) between them, applies to two adjacent oppositely charged bodies of any shape. An electric spark is a line of slip (a conducting line) and the energy of the electic field flows in upon the spark as it does upon a wire.
Page 78 - The magnetomotive force along the rod in this case is entirely independent of the shape and length of the rod and of the shape and size of the coil. It depends only upon the number of turns of wire in the coil and upon the strength of the current in the wire.

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