### тИ КщМЕ ОИ ВЯчСТЕР -сЩМТАНГ ЙЯИТИЙчР

дЕМ ЕМТОПъСАЛЕ ЙЯИТИЙщР СТИР СУМчХЕИР ТОПОХЕСъЕР.

### пЕЯИЕВЭЛЕМА

 еМЭТГТА 1 1 еМЭТГТА 2 7 еМЭТГТА 3 27 еМЭТГТА 4 35 еМЭТГТА 5 55 еМЭТГТА 6 67 еМЭТГТА 7 72 еМЭТГТА 8 73
 еМЭТГТА 10 82 еМЭТГТА 11 87 еМЭТГТА 12 111 еМЭТГТА 13 113 еМЭТГТА 14 122 еМЭТГТА 15 128 еМЭТГТА 16 135 еМЭТГТА 17 161

### дГЛОЖИКч АПОСПэСЛАТА

сЕКъДА 157 - ... if a straight line, &c. QED PROPOSITION 29. — Theorem. If a straight line fall upon two parallel straight lines, it makes the alternate angles equal to one another ; and the exterior angle equal to the interior and opposite upon the same side ; and likewise the two interior angles upon the same side together equal to two right angles.
сЕКъДА 22 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line. Let...
сЕКъДА 78 - IF a straight line be drawn parallel to one of the sides of a triangle, it shall cut the other sides, or those produced, proportionally; and if the sides, or the sides produced, be cut proportionally, the straight line which joins the points of section shall be parallel to the remaining side of the triangle...
сЕКъДА 177 - FBC ; and because the two sides AB, BD are equal to the two FB, BC, each to each, and the angle DBA equal to the angle FBC ; therefore the base AD is equal to the base FC, and the triangle ABD to the triangle FBC.
сЕКъДА 134 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.
сЕКъДА 177 - BK, it is demonstrated that the parallelogram CL is equal to the square HC. Therefore the whole square BDEC is equal to the two squares GB, HC ; and the square BDEC is described upon the straight line BC, and the squares GB, HC upon BA, AC.
сЕКъДА 97 - And since a radius drawn to the point of contact is perpendicular to the tangent, it follows that the angle included by two tangents, drawn from the same point, is bisected by a line drawn from the centre of the circle to that point ; for this line forms the hypotenuse common to two equal right angled triangles. PROP. XXXVII. THEOR. If from a point without a circle there be drawn two straight lines, one of which cuts the circle, and the other meets it ; if the rectangle...
сЕКъДА 27 - In any triangle, the square of a side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other side upon it.
сЕКъДА 177 - FC, and the triangle ABD to the triangle FBC. Now the parallelogram BL is double...
сЕКъДА 163 - This formula already proves, that if two angles of one triangle are equal to two angles of another, the third angle of the former must also be equal to the third of the latter ; and this granted, it is easy to arrive at the theorem we have in view.