| K. L. Armstrong - Encyclopedias and dictionaries - 1889 - 488 pages
...power necessary to elevate water to a given height, multiply the total weight of the water in fcs. **by the height in feet and divide the product by 33,000 (an allowance** of 25 per cent, should be added for water friction, and a further allowance of 25 per cent, for loss... | |
| Manfred Powis Bale - Pumping machinery - 1892 - 121 pages
...the height of lift required for the valve, which should equal one-fourth the diameter of the valve. **To find the Horse-power necessary to elevate water to a given height. — Multiply the** total weight of the column of water in pounds by the velocity per minute in feet, and divide the product... | |
| Handbooks, vade-mecums, etc - 1893 - 480 pages
...the horse power necessary to elevate water to a giveu height, multiply the total weight of the water **in pounds by the height in feet and divide the product by 33,000 (an allowance** of twenty-five per cent should be added for water friction, and a further allowance of twentyfive per... | |
| Aluminum Company of America - Aluminum - 1897 - 266 pages
...water to a given height. Multiply the total weight of the water to be elevated in one minute in ll>s. **by the height in feet, and divide the product by 33,000 (an allowance** of 25 per cent, should be added for water friction, and a further allowance of 25 per cent, for loss... | |
| Nehemiah Hawkins - Steam engineering - 1898 - 210 pages
...horse-power necessary to pump water to a given height ? Ans. Multiply the total weight of the water **in pounds by the height in feet and divide the product by 33,000.** Qnes. How do you find the pressure in Ibs., per square inch, of a column of water ? Ans. Multiply the... | |
| James Joseph Lawler - Hot-water heating - 1899 - 383 pages
...17.30 6 6.06 6.62 6 to 8 20.69 22.:i8 7 7.02 7.62 Special. 26.28 27.77 8 7.98 8.62 Special. 29.88 33.69 **To find the horse-power necessary to elevate water...elevated per minute in pounds by the height in feet, and** divided the product by 33,000 (an allowance should be added for water friction, and a further allowance... | |
| Norfolk Creosoting Co - Building materials - 1900 - 92 pages
...square the diameter of the water cylinder in inches and multiply by 4. Example: Capacity of a 5-inch **cylinder is desired. The square of the diameter (5...necessary to elevate water to a given height, multiply the** tolal weight of the water in pounds by the height in feet, and divide the product by 33,000 (an allowance... | |
| Nehemiah Hawkins - Steam-boilers - 1900 - 331 pages
...multiplied by 4, gives 100, the number of gallons per minute (approximately). To find the horse power **necessary to elevate water to a given height, multiply the weight of the water elevated per minute in** Ibs. by the height in feet, and divide the product by 33,000 (an allowance should be added for water... | |
| American Well Works (Aurora, Ill.) - Technology & Engineering - 1900 - 224 pages
...the horse-power required to elevate water to a given height, .nultiply the total weight of the water **in pounds by the height in feet and divide the product by** 33.000. An allowance should .be made for losses by friction and condensation. t'se Air Chamber on long... | |
| Nehemiah Hawkins - Steam engineering - 1901 - 319 pages
...horse power necessary to pump water to a given height. EULE. Multiply the total weight of the water **in pounds, by the height in feet, and divide the product by 33,000.** PUMPS. EXAMPLE. What power is required to elevate 90,800 Ibs. of water 45 ft. ' 90,800 45 454000 363200... | |
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