## Tables for Finding the Strains in Railway Bridge Trusses Under the Action of a Concentrated Load System |

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20 tons 33 feet 33 tons 40 Span 44 feet 56 feet 79 SPAN apex brace calculated centre of moments CONCENTRATED LOAD SYSTEM distance from left equivalent uniform load EXPLANATION OF TABLE feet from left flange formula found from Table g Pi give greater moments gives at once greater strains hence including 120 interpolate l1mit left end length of span limit is 89J load per unit locomotive excess maximum shear pounds per foot Pu Span Put this equal reaction rolling load S4 Pi second wheel shear found shear is required Sl'AN span 90 feet span given span of 200 strains due STRAINS IN FRAMED system must rest tabic table for corresponding table gives table on right tributed load TRUSSES uniform moving load uniformly uniformly dis values wheel at point X below X Аз Мх Ръ