## Elementary Algebra: First[-second] Year Course, Volume 1 |

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algebraic expression answer arithmetic binomials called coefficient complete divisor Complete the square cost descending powers difference digit dimensions Diophantus distance Divide both sides dividend division dollars Draw a graph Egyptian mathematical equal factors exceeds exponent Find the number Find the square FLORIAN CAJORI fraction Hence Hindu-Arabic numerals imaginary numbers income integer less letter linear equation magic square means miles an hour monomial Multiply both sides negative number numerator and denominator obtain ORAL EXERCISES parenthesis perfect square perimeter polynomial positive number pounds problem quadratic equation quotient radical sign ratio rectangle remainder result rule rule of signs selling price Simon Stevin Simplify solution Solve the following square root straight line Substitute subtract temperature train Transpose trial divisor triangle trinomial Type form unknown weight width write yard zero

### Popular passages

Page 160 - AB into two parts, so that the rectangle contained by the whole line and one of the parts, shall be equal to the square on the other part.

Page 51 - Multiply the numerators together for a new numerator, and the denominators together for a new denominator.

Page 50 - That is, the exponent of a letter in the quotient is equal to its exponent in the dividend minus its exponent in the divisor. For example, — = a*~".

Page 161 - the second value is in this case not to be taken, for it is inadequate ; people do not approve of negative roots.

Page 111 - Multiply each term of one polynomial by each term of the other polynomial and then simplify.

Page 117 - The square root of a fraction may be found by taking the square root of the numerator and the square root of the denominator, and making them the numerator and denominator of a new fraction, thus V4o^_2a 8lP"*9F

Page 199 - A mule and a donkey were going to market laden with wheat. The mule said : " If you give me one measure, I should carry twice as much as you ; but if I give you one, we should have equal burdens.

Page 149 - If he had received $1 a day less than he did, he would have been obliged to work 5 days longer to earn the same sum. How many days did he work ? Generalize.

Page 169 - The product of all the different factors, each factor being taken the greatest number of times it occurs in any of the given expressions, is the lowest common multiple required.

Page 144 - Completing the square by adding to each side the square of half the coefficient of the second term, 3?