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The Inductive Algebra, Embracing a Complete Course for Schools and Academies
William J 1843-1914 Milne
No preview available - 2016
The Inductive Algebra: Embracing a Complete Course for Schools and Academies
William James Milne
No preview available - 1881
acres added algebraic arithmetical progression arithmetical series binomial cents changed Clearing of fractions coefficient complete divisor Completing the square cube root digits Divide dividend division dollars equal factors exact divisor Expand Explanation.—Since Extracting the square factor will rationalize Find the cube Find the logarithm Find the number Find the square Find the sum find the values fourth power fractional exponents geometrical progression geometrical series Give the rule greatest common divisor last term least common denominator least common multiple literal quantities mantissa miles mixed quantities monomial multiplied negative quantity number of terms numbers in arithmetical obtained polynomial positive quantity prime factors principle relating Principles.—1 PROCESS proportion quadratic equation quan quotient radical quantity radical sign ratio second member second power second term SOLUTION Solve an example square root subtract third power three numbers tion tities Transposing trial divisor twice unknown quantities x2 f yards
Page 60 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient.
Page 113 - Subtract the numerator of the subtrahend from the numerator of the minuend, and place the difference over the common denominator.
Page 182 - Find the square root of the first term, write it as the first term of the root, and subtract its square from the given polynomial. Divide the first term of the remainder by...
Page 186 - Add to the trial divisor the figure last found, multiply this complete divisor by the figure of the root found, subtract the product from the dividend, and to the remainder annex the next period for the next dividend.
Page 189 - Tlie result will be the complete divisor. Multiply the complete divisor by the last term of the root found, and subtract this product from the dividend.
Page 256 - That is, in any proportion either extreme ' is equal to the product of the means divided by the other extreme ; and either mean is equal to the product of the extremes divided by the other mean.
Page 52 - The square of the difference of two quantities is equal to the square of the first, minus twice the product of the first and second, plus the square of the second.
Page 46 - Multiply each term of the multiplicand by each term of the multiplier, and add the partial products.