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allel angles equal axis base multiplied bases and equal bisect called centre chains chord circle whose diameter circumference common intersection cone convex surface cubes cubic cylinder decimal dicular divided equal altitudes equal bases equal Bk equal to half equivalent find the area four quantities frustum given line given point half the arc half the product hence hexagon homologous sides hypothenuse inches included angle inscribed inscribed circle interior prisms length Let ABCD lower base measured by half Mensuration of Surfaces nonagon number of sides parallelogram parallelopipedon pendicular perimeter perpen perpendicular polyedron polygon ABCDE PROBLEM pyramid S—ABCDE quadrilateral radii radius Ratios and Proportions rectangle regular polygon Required the area rhombus right angled triangle right angles Bk scribed similar polygons similar triangles slant height solid squares described straight line tangent THEOREM trapezoid triangle ABC triangular prism triangular pyramid upper base vertex
Page 97 - If two triangles have two sides and the included angle of the one, equal to two sides and the included angle of the other, each to each, the two triangles will be equal in all their parts." Axiom 1. "Things which are equal to the same thing, are equal to each other.
Page 12 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Page 59 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Page 131 - If a cone be cut by a plane parallel to the base, the section will be a circle.
Page 91 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Page 174 - To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and then divide the product by two : the quotient will be the area (Bk.
Page 34 - Hence, the interior angles plus four right angles, is equal to twice as many right angles as the polygon has sides, and consequently, equal to the sum of the interior angles plus the exterior angles.
Page 90 - Two triangles of the same altitude are to each other as their bases ; and...