| Peter Nicholson - Mathematics - 1825 - 372 pages
...the sine of that angle measured in the circle ; therefore the sides of the triangle are to each other **as the. sines of the opposite angles measured in the...consequently as the sines of the same angles measured in** a circle whose radius is that of the tables. Hence the following proposition of such frequent use in... | |
| William Hill (land surveyor.) - 1847
...the sine of that angle measured in the circle ; therefore the sides of the triangle are to each other **as the sines of the opposite angles measured in the...Trigonometry. In any triangle, the sines of the angles** measured by any one circle are proportional to the sides opposite those same angles. In our plan of... | |
| Robert Potts - 1855
...nearest him (from which his distance is a) in a straight line. Find the radius of the curve. 6. Shew that **in any triangle the sines of the angles are proportional to the** opposite sides. 8. Prove that for all values of m, cos mO + -J{- 1) sin mO is a value of {cos 0 + V(-... | |
| Thomas Kimber - 1865
...+ g = . Account for the value of tan. A + В given by this formula, if A = В = 45°. 13. In every **triangle the sines of the angles are proportional to the sides opposite** to them. Find the area of the triangle whose sides are 30, 40, 50 feet. 14. Given two angles and a... | |
| Cambridge univ, exam. papers - 1870
...particular case. /o Having given that cos 330° = ~ , find the cosine and sine of 165°. 4. Prove that, **in any triangle, the sines of the angles are proportional to the sides** respectively opposite to the angles, and that any side divided by the sine of the opposite angle, is... | |
| Thomas Kimber - 1880
...В . — Account for the value of tan. A + В given by this formula, if A s= В = 45°. 18. In every **triangle the sines of the angles are proportional to the sides opposite** to them. Find the area of the triangle whose sides are 30, 40, 50 feet. 14. Given two angles and a... | |
| Robert Hamilton Pinkerton - Trigonometry - 1884 - 176 pages
...magnitude from 0° up to 180°, but that the angle VES will always be limited in magnitude. Now, since **in any triangle the sines of the angles are proportional to the** opposite sides, whatever be the positions of V and E, we have the equation sinSEV_VS_5 sinSVE ~ ES... | |
| International Correspondence Schools - Engineering - 1897 - 318 pages
...a triangle given to find the other two sides AB and C B. In Trigonometry, it is demonstrated that, **in any triangle the sines of the angles are proportional to the** lengths of the sides opposite to them. In other words, sin A : sin B :: BC : AC; or, sin A : sin U... | |
| International Correspondence Schools - Surveying - 1898
...method, however, is the following: In higher works on trigonometry, it has been demonstrated that, **in any triangle, the sines of the angles are proportional to the** lengths of the sides opposite to them. In other words, sin A : sin B::BC : AC; or, sin A : sin C:;BC... | |
| International Correspondence Schools - Civil engineering - 1899
...method, however, is the following: In higher works on trigonometry, it has been demonstrated that, **in any triangle, the sines of the angles are proportional to the** lengths of the sides opposite to them. In other words, sin A : sin B::BC:AC; or, sin A : sin C:: BC... | |
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