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9 X vermilion amount of crossing-over appeared bar 9 bar fused body-color bred cfcf cherry club cherry vermilion chromosome club vermilion cross Cross-over values cultures daughters were back-crossed double cross-over double crossing-over double recessive Drosophila eosin vermilion experiment eye-color facet females gave Fi wild-type flies forked fused fused males gave the results gave wild-type gens gray H. J. Muller heterozygous inbred gave lemon lethal factor lethal sa lethal sb linked character locus males and females mated milion bar milion sable miniature Morgan mutant mutant type Non-cross-over non-disjunction normal allelomorph not-bar ratio reduplicated Reference results shown rudimentary forked sable bar sable males sex factor sex-linked characters sex-linked factors sex-ratio shown in table sons synapsis thorax Total vermilion 9 vermilion fused vermilion males vermilion sable viability wild 9 9 wild females wild type wild-type 9 wings X chromosome Yellow club yellow sable
Page 86 - ... the genes as linear. Surely this same data could legitimately be used in testing the hypothesis that the arrangement is non-linear. Moreover the Table 65 is, so far as I know, the only table in which the authors have ever given a comprehensive summary of their data. At the head of the table, they say "In Table 65 all data so far secured upon the sex-linked characters are summarized.
Page 16 - Whatever the nature of the lethals' action, it can be shown that from among the offspring obtained from certain stocks expected classes are missing, and the absence of these classes can be accounted for on the assumption that there are present mutant factors that follow the Mendelian rule of segregation and which show normal linkage to other factors, but whose only recognizable difference from the normal is the death of those individuals which receive them.
Page 22 - ... such a color blind male (or any color blind male in fact) is mated with a female having this origin, half of the daughters will be color blind, half normal; half of the sons will be color blind, half will be normal. In other words the color blind grandmother transmits her defect to all of her sons, and to half of her granddaughters and to half of her grandsons. The inheritance of the chromosomes and of the defect is strictly parallel in this case also, as seen in the diagram (fig. 3). In the...
Page 11 - XX female must be due to an aberrant reduction division at which the two X chromosomes fail to disjoin from each other. In consequence both remain in the egg or both pass into the polar body.
Page 11 - Ordinarily all the sons and none of the daughters show the recessive sex-linked characters of the mother when the father carries the dominant allelomorph.
Page 11 - But that the Y does play some positive role is proved by the fact that all the XO males have been found to be absolutely sterile.
Page 26 - The system of symbols used in the diagrams and table headings is as follows: The...
Page 8 - Here, over a hundred characters that have been investigated as to their linkage relations are found to fall into four groups, the members of each group being linked, in the sense that they tend to be transmitted to the gametes in the same combinations in which they entered from the parents.