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A B D A B is equal A C B adjacent Angles Angle ABC Angle BAC bisected Centre Circle A B C D Circumference Cone Cylinder D E F demonstrated described Diameter drawn equal Angles equiangular Equimultiples Euclid f equal fame Altitude fame Multiple fame Plane fame Proportion fame Reason fore given Right Line Gnomon greater homologous join less Logarithm Magnitudes Neper Number parallel Parallelogram perpendicular Polygon Prism PROPOSITION Ratio rectangle rectangle contained remaining Angle Right Angles Right Line A B Right-lined Figure Segment similar Sine solid Angle squareof Squares of A C Subtangent subtending T E T Theorem thro tiple Triangle ABC Unity Vertex the Point Wherefore whole
Page 197 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Page 23 - If two triangles have two sides of the one equal to two sides of the other, each to each ; and have likewise the angles contained by those sides equal to each other; they shall likewise have their bases, or third sides, equal; and the two triangles shall be equal; and their other angles shall be equal, each to each, viz. those to which the equal sides are opposite.
Page 240 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 9 - ... sides equal to them of the other. Let ABC, DEF be two triangles which have the two sides AB, AC equal to the two sides DE, DF, each to each, viz. AB equal to DE, and AC to DF ; but...
Page 89 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.
Page 151 - A straight line is said to be cut in extreme and mean ratio, when the whole is to the greater segment as the greater segment is to the less.
Page 52 - CB, and to twice the rectangle AC, CB: but HF, CK, AG, GE make up the whole figure ADEB, which is the square of AB ; therefore the square of AB is equal to the squares of AC, CB, and twice the rectangle AC, CB. Wherefore, if a straight line be divided, &c.
Page 25 - EF (Hyp.), the two sides GB, BC are equal to the two sides DE, EF, each to each. And the angle GBC is equal to the angle DEF (Hyp.); Therefore the base GC is equal to the base DF (I.
Page 34 - ... therefore their other sides are equal, each to each, and the third angle of the one to the third angle of the other (26.
Page 198 - ABC, and they are both in the same plane, which is impossible ; therefore the straight line BC is not above the plane in which are BD and BE: wherefore, the three straight lines BC, BD, BE are in one and the same plane. Therefore, if three straight lines, &c.