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acid angle antimony applied beam beeswax bismuth blue boil borax Brass breadth cast-iron cement centre chord circle circumference color Copal copper Cube Root cubic feet curvature curve cylinder decimal deflexion DEGEEES DEGREES Diam diameter Dissolve distance divide dovetail equal Example external secant foot force gallons given glass glue Gold heat horse power iron isinglass lamp-black lead length lever linseed oil Logarithm manganese Marble mastic Melt metal minute Multiply nitric acid oil of turpentine ounces oxide paper pearlash perpendicular piece of timber pint potash pounds pressure Prussian blue quantity quotient rectified spirit Rule sal-ammoniac shell-lac silver solid solution spirit square inch square root steam stone strain sulphate surface TABLE tangent thickness tons Varnish velocity vessel vinegar wheel wood yellow zinc
Page 39 - To find the solidity of a spheroid. RULE. Multiply the square of the revolving axis by the fixed axis, and by *5236, and the product will be the solidity.
Page 27 - Of four-sided figures, a square is that which has all its sides equal, and all its angles right angles.
Page 267 - ... they are dissolved. Then mix the whole with a sufficient heat. Keep the glue in a phial closely stopped, and when it is to be used, set the phial in boiling water.
Page 266 - ... and, in another vessel, dissolve as much isinglass, previously a little softened in water, (though none of the water must be used), in French brandy or good rum, as will make a...
Page 235 - SOLDERS. For Lead. — Melt one part of block tin, and, when in a state of fusion, add 2 parts of lead. Resin should be used with this solder. For Tin. — Pewter, 4 parts ; tin, 1 ; bismuth, 1. Melt them together and run them into slips.
Page 38 - RULE. — To the sum of the areas of the two ends add the square root of their product ; multiply this sum by the perpendicular height, and -^ of the product is the solid content.
Page 128 - Bring the edges of the pieces of shell to fit each other, observing to give the same inclination of grain to each, then secure them in a piece of paper, and place them between hot irons or pincers ; apply pressure, and let them cool.
Page 65 - RULE. — Divide the weight to be raised by twice the number of pulleys in the lower block ; the quotient will give the power necessary to raise the weight. EXAMPLE. — What power is required to raise 600 Ibs., when the lower block contains six pulleys ? 600 6 x 2 = 50 Iks., Ans.
Page 53 - To find the centre of Gyration, multiply the weight of the several particles by the squares of their distances from the centre of motion, and divide the sum of the products by the weight of the whole mass; the square root of the quotient will be the distance of the centre of gyration, from the centre of motion.