| James Thompson - Arithmetic - 1808 - 172 pages
...area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply **the sum of the parallel sides by the perpendicular distance between them,** and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel... | |
| Matthew Iley - 1820
...Area of a Quadrilateral wherein two unequal Sides are Parallel to one another. RULE. Multiply half **the sum of the parallel sides by the perpendicular distance between them,** and the product will be the area. Let ABCD be a quadrilateral, wherein AC and BD are parallel but unequal;... | |
| Anthony Nesbit - Measurement - 1824 - 434 pages
...is its area ? Ans. 1131^.2 in. 9 pa. PROBLEM VIII. To find the area of a Irapezoid. RULE. Multiply **the sum of the parallel sides by the perpendicular distance between them,** and half the product will be the area. Or, half the sum of the sides multiplied by their distance will... | |
| Thomas Hornby (land surveyor.) - Surveying - 1827 - 270 pages
...00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply **the sum of the parallel sides by the perpendicular distance between them,** and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel... | |
| John Bonnycastle - Geometry - 1829 - 252 pages
...the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply **the sum of the parallel sides by the perpendicular distance between them,** and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides... | |
| Edinburgh encyclopaedia - 1830
...trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply **the sum of the parallel sides by the perpendicular distance between them,** and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities... | |
| Tobias Ostrander - Measurement - 1834 - 129 pages
...EXAMPLES. 1. 24,46 + 38,40 = 62,86 chains the sum of the two parallel sides ; then 62,86 X 16,2 = 1018,332 **the product of the sum of the parallel sides by the perpendicular** ; then 2)1018,332 = 509,166 square chains ; then 10)509,166 = 50,9166 acres = 50 acres, 3 roods, and... | |
| William Galbraith - Astronomy - 1834 - 428 pages
...Trapezium. — Multiply the base into half the sum of the perpendiculars. 4. Trapezoid. — Multiply half **the sum of the parallel sides by the perpendicular distance between them.** fi. Irregular Polygon. — Divide it into triangles, find their areas, the sum of these will be the... | |
| Robert Simson (master of Colebrooke house acad, Islington.) - 1838
...16s + 122 = 20, the length of the hypotenuse. HoW do you find the area of a trapezoid ? Multiply half **the sum of the parallel sides by the perpendicular distance between them,** and the product will be the area of the trapezoid. What is the area of a trapezoid, its parallel sides... | |
| Charles Davies - Geometrical drawing - 1840 - 252 pages
...the breadth of the Ans. 77,8875 feet. PROBLEM VI. 13. To find the area of a trapezoid. RULE. Multiply **the sum of the parallel sides by the perpendicular distance between them,** and then divide the product by two : — the quotient will be the area. EXAMPLES. DC 1. Required the... | |
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