## The Power Catechism: Correct Answers to Direct Questions Covering the Main Principles of Steam Engineering and the Transmission of Power. Compiled from the Regular Monthly Issues of "Power"... |

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### Common terms and phrases

A.—About A.—Because A.—Multiply A.—They absolute pressure amount belt bolt brick carbon chimney Circular Area Circular Segments Circum coal column combustion crank cross-head cubic foot cut-off cylinder degrees Diameters of Circles distance divide double eccentric engine equal evaporation factor of safety feed feed-water ference fire fire-box flue formula friction fulcrum furnace fusible plugs gage gases give given grate heat-units heater heating surface heating-surface horse-power inches in diameter increase injector latent heat length lever mean effective pressure molecules multiplied opening oxygen pipe piston speed plate port position pound of water pounds per square pulley quotient revolutions per minute right angles riveted joint rule safety-valve shaft shearing shearing strength shell shown in Fig sixth column square feet square inch square root stem stroke Table temperature tensile strength total heat tubes tubular boiler valve velocity wall weight width wrist-plate

### Popular passages

Page 26 - ... fuse by the heat of the furnace, whenever the water in the boilers falls below its prescribed limits; and that adequate and certain provision is made for an ample supply of water to feed the boilers at all times, whether such vessel is in motion or not, so that in highpressure boilers the water shall not be less than four inches above the top of the flues; and that means for blowing out are provided, so as to thoroughly remove the mud and sediment from all parts of the boilers, when they are...

Page 39 - ... and divide by the radius or half diameter, also expressed in inches; and the result will be the pressure allowable per square inch of surface for single riveting, to which add 20...

Page 54 - X 144 -13 = 140 pounds working pressure. 144 Plates with bolts with double nuts and a washer at least onehalf the thickness of the plate, and a size equal to two-fifths the pitch of stay-bolts, would be allowed with a constant 200, when riveted to plates, by rule as above. EXAMPLE: — A plate 3-4 inch thick, with a washer 3-8 inch thick and 5.6 inches square, supported by bolts 14-inch 200 X 144 center, would be - - = 147 pounds working pressure.

Page 29 - Banca tin, at least one-half inch in diameter at the smallest end of the internal opening, in the following manner, to wit: Cylinder boilers with flues shall have one plug inserted in one flue of each boiler; and also one plug inserted in the shell of each boiler from the inside, immediately before the fire line, and not % less than four feet from the forward end of the boilers. All...

Page 53 - ... the square of the thickness of the plate in sixteenths of an inch. Divide this product by the square of the pitch or distance from center to center of the stay-holes.

Page 29 - ... said plugs to conform in construction with plugs now authorized to be used by this Board; and it shall be the duty of the inspectors to see that these plugs are filled with Banca tin at each annual inspection.

Page 130 - SECTION XL HORSE-POWER OF ENGINES. Q. 534 — How are steam engines rated? A. — By horse-power. Q. 535 — What is a horse power? A. — 33,000 foot-pounds per minute, 550 foot-pounds per second, or 1,980,000 foot-pounds per hour. Q. 536 — What is a foot-pound? A. — One pound of force exerted through one foot of space. Q. 537 — How many foot-pounds of work are required to lift one pound one hundred feet? A. — One hundred. Q. 538 -—How many foot-pounds are required to lift loopounds one...

Page 171 - Multiply the diameter of the driven by its number of revolutions, and divide the product by the number of revolutions of the driver : the quotient will be the diameter of the driver.

Page 116 - ... gives a liberal allowance because with first-class installations the coal consumption would not be as great as 5 pounds per horsepower per hour. The large allowance is made to cover the use of poor coal or the forcing of the boilers on account of overloads. Rule. — Divide the horsepower by 3.33 times the square root of the height. The quotient will be the required effective area, in square feet. To the diameter so found add 4 inches to compensate for friction. EXAMPLE. — What should be the...