## Key to the High School Algebra: Containing Solutions of the More Difficult Examples |

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### Common terms and phrases

_ x2 20 dollars A's age A's capital A's money A's share a8 Trial divisor B's age B's rate breadth cents characteristic we know Clearing and transposing Completing square corresponding number cube root Difference of mantissas distance Dividing the terms Equating coefficients equation becomes Expanding Extracting root Extracting square root Factoring feet fourth remainder gallons Given mantissa hence integral figures KEY H. S. length Let x represent Logarithm Mantissa next less Mantissa of log miles per hour minute-spaces Number corresponding number of days number of sheep Principle rate per hour Rationalizing the denominator represent A's represent the number rods scale of relation second remainder Simplifying Solve as Ex Substituting in Ex Substituting in formula sum given Taking square root third remainder Transposing and dividing Transposing and squaring traveled whence whole number x2 _

### Popular passages

Page 314 - The square on the hypotenuse equals the sum of the squares on the other two sides.

Page 225 - A trinomial belongs to this type, ie it is a perfect square, when two of its terms are perfect squares, and the remaining term is equal to twice the product of the square roots of these terms.

Page 33 - In any trinomial square (Art. 108), the middle term is twice the product of the square roots of the first and third terms ; hence the square root of the third term is equal to the second term divided by twice the square root of the first.

Page 78 - Then - = the part both can do in 1 day, x — = the part A can do in 1 day, a and - = the part B can do in 1 day.

Page 219 - Transposing 50 x* + 300 x = 3600, whence a;2 + 6 x = 72, and x = 6 or — 12, 450 = 750. Hence $7.50 was the price of the pasture per week. Ex. 5. There are four numbers in arithmetical progression, the product of the extremes being 22, and that of the means 40. What are the numbers ? Let...

Page 111 - ... x = 15 . (2) and x -\- у = z (3) Substituting (3) in (1), 2 z = 146 (4) Whence, z = 73 (5) Therefore, from (3), x -\- у — 73 (6) Equation (2), ( — x + у — 15 Adding (6) and (2), 2...

Page 209 - ... more than the men. How many men and women were there ? Let x = the number of women, And y = the number of men. Then the women will have expended I6x, and the men 25y, so that I6x=25y + l.

Page 209 - Let x and у represent the numbers ; then, x — у = 15; (1) and, & = f.

Page 91 - Let x represent the number of days in which both can do it...

Page 319 - ... equal to the sum of an arithmetical series whose first term is...