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A Key of Solutions to Examples in Eaton's Common School Arithmetic
James H Eaton
No preview available - 2015
100 per cent 11 spaces 12 round 1st assumption 1st bill due 1st error 1st Payment 1st Remainder 2d assumption 2d error 2d Payment 2d Principal 2d Remainder 4th Payment 7fur A's expenses A's gain acres amount of $1 Arithmetic Assume B's share B's stock carats cassimere circumference common difference COMPOUND convex surface cost cows cubic foot diameter difference of extremes distance from 12 distance round divided equals examples EXPLANAT1ON forming the 2d gallon gives greater extreme greatest common divisor h. h. moves Hence hight horse inches June 15 kilom last term length loss lower base metic minuend NOTE number multiplied oxen Prop radius rank contains ratio less rods sheep side solution solved Subtract Subtrahend sum received total gain upper base width Акт
Page 91 - That is, each grade is multiplied by the corresponding prescribed weight, and the sum of the products is divided by the sum of the weights. In like manner the rating of applicant A
Page 104 - If a cone is cut by a plane parallel to the base, the portion of it between this plane and the base is called a frustum of the cone. The section by the plane is called the upper base, and the perpendicular distance between the bases is the altitude. The volume of a frustum of a cone is given by precisely the same formula as the respective one for the...
Page 97 - ... similar figures are to each other as the squares of their homologous sides.
Page 57 - To find the time in which any sum will double itself, at any rate per cent., divide 100 by the rate, and the quotient will be the time in years. 8. In how many years will $50 amount to $100, it being on interest at 8 per cent. ? Ans. 12yr. 6m. 9. How long will it take any sum of money to double itself on interest at 6 per cent. ? 10. In what time will a sum of money triple itself on interest...
Page 116 - Consequently, to combine these two conditions, thq property must be divided in such a manner, that the son may have twice as much as the mother, and the mother twice as much as the daughter.
Page 122 - Hence it appears, he gained -fa of a cent on each lemon, which is 1 cent on 14 lemons. Therefore he bought 14 X 25 = 350 lemons. 57. 8^ barrels. 58. To answer this question, the 12 hours from noon to midnight are to be divided into 2 parts, in the ratio of 4 to 5. 4+5=9; \ of 12 is \\\ 1^X4 is 5^.