 | Abel Flint - Surveying - 1813 - 214 pages
...the lust Product will be double the Area of the Triangle. Nat. Sine of the Angle 28° 5'. 0.47076. 105X85=8925, and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezovl. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between... | |
 | P. O'Shaughnessy (Civil engineer) - Civil engineering - 1848 - 110 pages
...of a triangle, having the base 82 chains and the altitude 20. 12 chains. Ans. 82a lr 3|P. Prob. 3. To find the area of a trapezoid. Rule — Multiply half the sum of the two perpendiculars by the base, and the product will be area. (The truth of this rule is manifest, as the... | |
 | Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...318. ATRAPEZOID is a quadrilateral, which has only one pair of its opposite sides parallel. ART. 319. To find the area of a trapezoid. RULE. — Multiply half the sum of the parallel sides by the altitude, and the product is the area. 1. What is the area of a trapezoid, the... | |
 | Alexander Ingram - 1851 - 202 pages
...diagonal 127 poles. Ans. 3661-8734 per. = 22 ac. 3 ro. 21 per. 26 yds. 3'78 ft. QUADRILATERALS. PROB. VII. To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides by the perpendicular from the one to the other. That is, ^(AD + BC) X AE = the area.... | |
 | Benjamin Greenleaf - 1854 - 342 pages
...318. A TRAPEZOID is a quadrilateral, which has only one pair of its opposite sides parallel. ART. 319. To find the area of a trapezoid. RULE. — Multiply half the sum of the parallel sides by the altitude, and the product is the area. 1. What is the area of a trapezoid, the... | |
 | Andrew Duncan (Surveyor) - Surveying - 1854 - 156 pages
...between B and C. Fences from F, G, and A, to P, trisect the farm, which is plain from the figure. 15th. To find the area of a Trapezoid Rule, multiply half the sum of the parallel sides by the perpendicular distance between them, and the product is the area. Let figure... | |
 | Elias Loomis - Trigonometry - 1855 - 192 pages
...to one fourth the square of one of its sides multiplied by the square root of 3. PROBLEM III. (87.) To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides into their perpendicular distance. For demonstration, see Geometry, Prop. 7, B. IV.... | |
 | Elias Loomis - Logarithms - 1859 - 372 pages
...one of its sides multiplied by the square root of 3. MENSURATION OF SURFACES. 63 PROBLEM III. (87.) To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides into their per . pendicular distance. For demonstration, see Geometry, Prop. 7, B. IV.... | |
 | Charles Davies - Arithmetic - 1863 - 346 pages
...ABCD, having two of its sides, AB, DC, parallel. The perpendicular, CE, is called, the altitude. 393. To find the area of a trapezoid. Rule. — Multiply half the sum of the two parallel lines by the altitude, and the product will be the area. (Bk. IV., Prop. VII.) Examples. 1. Required... | |
 | Edward Thomas Stevens - 1866 - 434 pages
...which has only two of its opposite sides parallel, as ABD c. AE is the perpendicular. c K u To Jind the area of a trapezoid. RULE : — Multiply half the sum of the parallel sides by tho perpendicular distance between them ; the product is the area. DD THE CIRCLE.... | |
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To find the area of a trapezoid. RULE. — Multiply half the sum of the parallel sides by the altitude, and the product is the area. 
