Commentary on the Maya Manuscript in the Royal Public Library of Dresden

Front Cover
 

What people are saying - Write a review

We haven't found any reviews in the usual places.

Other editions - View all

Common terms and phrases

Popular passages

Page 113 - Seler). 1,364.360, therefore, is a Huna of lunar revolutions multiplied by the number of days in the Mercury period. Later on we shall find the lunar revolution fixed at 29f days. 3) 1,366,560. This is the most comprehensive number of the entire Manuscript, for it is divisible into each of the following periods: — Those of the Senores de la noche or Lords of the Cycle (9 X 151,840; this is, however, the first number of the top row), the Tonalamatls (260X5256), the old official years (360 X 3796)...
Page 156 - Muluc and which we eaw before in the sixth place among the hieroglyphs on the right side of page 34. Pages 35 b— 37 b. I 11 XII 6 V 9 I 4 V 7 XII 9 VIII 6 I Caban That is, a regular Tonalamatl of five parts, 5 X 52. Muluc That the 52 days are divided into two halves Imix (11 + 6 + 9 = 4 -f 7 + 9 + 6), may only be Ben accidental.
Page 179 - V Oc (8) XIII Ezanab (17) IV Men (8) XII Akbal (8) VII Chuen (8) II Cauac (8) X Manik (8) V Men (8) Thus the days Chicchan, Lamat, Oc, Ben, Men, Ezanab, Ahau, and Akbal are repeated here twice, and the others occur but once. The 4 (17+48) strongly recalls the 4 (19+46 ) on pages 31b-35b. The repetition of six times eight days in each quarter of the Tonalamatl...
Page 201 - The average, 29.5, however, is too short for the length of the lunar revolution. In order to raise it as nearly as possible to the exact time, two other numbers were introduced at certain points of the series, viz : — 148= 2 X 29+3 X 30, 178=2 X 29+4 X 30. 148=5 months of 29.6 days, while 178=6 months of 29 f days.
Page 179 - Akbal (17) IV Ahau (8) XII Lamat (8) VII Cib (8) II Kan (8) X Eb (8) V Ahau (8) XIII Lamat (17) IVChicchan(S) XII Ben (8) VIIImix(8...
Page 121 - Cyrus Thomas first made the important discovery that these pages represent the transition from one year into the next, but held the erroneous opinion that the last two days of each of the four kinds of years were treated of on each page. While Seler, on the other hand, found that we have here to do with the last day of one year and the first of the following year, and that, therefore, Ben, Ezanab, Akbal and Lamat are the beginnings of the years and thus of the 20-day periods. The years, however,...
Page 111 - Ahau 18 Zip. First let me observe that I have restored the four large numbers at the top, which are almost entirely effaced, as follows: — 1 15 10 5 1 16 10 5 1 6 16 8 14 0 00. 0 And furthermore, at the right, bottom, I have substituted the third month for the second of the Manuscript, which preceeding will be justified later on. The least difficult portion of the contents of this page is the first series consisting of 16 members, each being a multiple of 2920. It begins with the date I Ahau (which...
Page 200 - Thus far we have examined only the upper halves of pages 51 and 52 and have still to consider the lower, but not until we have finished the upper parts of pages 53-58 of which the former are the continuation. We have first to consider the series, then the pictures and lastly the hieroglyphs. As on page 24 we found multiples of the number 2920 (=8 X 365=5 X 584), while on pages 46-50 it was divided into four unequal parts, so on pages 51-52 we find multiples of the number 11,960 (104 X 115=46 X 260)...
Page 159 - ... in which a small human being seems to be emerging from a snail (the symbol of birth). Above the water is B, grasping a serpent which is in the water, as if to protect the newborn being from the serpent. The twenty-fifth (with Kin) is the so-called bat-god, who on page 50 at the left ends the series of twenty gods. The twenty-seventh sign (with Yax) is still undetermined. Pages 38 b — 41 b. VI 16...
Page 200 - X 37,960. normal date 4 Ahau 8 Cumhu (9 Ix). But below this, between red numerals denoting the 1,578,988 mentioned above, there is set down in black the number 1,268,800. This corresponds to the date IV Ahau 3 Zip (2 Cauac). It may have been formed by adding 16,120 = 62X260 to 11 Ahau-Katuns= 1,252,680. It is, however, not only equal to 4880 X 260, but also to 158,600 X 8, therefore also divisible by the interval between IV Ahau XII Lamat, as well as by 104 = 8 X 13, while on the contrary it is not...

Bibliographic information