| Euclid, Robert Simson - Euclid's Elements - 1806 - 518 pages
...is, *he given ratio of AD to BC, must be less than the ratio of GH to EF, which the straight line, in **a segment of a circle containing an angle equal to the given angle,** that bisects the base of the segment at right angles, has unto the base. Con. 1. If two triangles,... | |
| Miles Bland - Geometry - 1819 - 377 pages
...opposite to it, and the sum of the other two sides ; to construct the triangle. Let AB be the given side. **Upon it describe a segment of a circle containing an angle equal to** half the given angle ; and from A draw AC equal to the given sum of the two sides ; join EC-, and make... | |
| Geometry - 1821 - 438 pages
...one of the angles at the base, and the other angle at the base ; to construct the triangle. Let AB he **equal to the given bisecting line ; and upon it describe...GDH parallel to AB. In FB produced take BI equal to** EH. Join AI; A FI is the triangle required. Join IG, cutting AB in K. Because GHis parallel to AB,... | |
| Sir John Leslie - Curves - 1821 - 448 pages
...D(V and COc are likewise given. COMPOSITION. Draw any diameter KO, on which describe (III. 23. El.) **a segment of a circle containing an angle equal to the given** inclination of the conjugate diameters, and meeting the curve in a point G, join GE, G?, and parallel... | |
| Miles Bland - Geometry - 1827 - 377 pages
...the given vertical angle. (15.) Given the line bisecting the vertical angle, the perpendicular dravm **to it from one of the angles at the base, and the...ED, and produce it to F; join FA, FB ; and through** A draw GDH parallel to AB. In FB produced take BI equal to BH. Join AI; API is the triangle required.... | |
| Robert Simson - Trigonometry - 1827 - 513 pages
...the given ratio of AD to BC, must be less \ than the ratio of GH to KF, which the straight line in **a segment of a circle containing an angle equal to the given angle,** that bisects the base of the segment at right angles, has unto the base. COR. 1. If two triangles,... | |
| Henry Parr Hamilton - Conic sections - 1834 - 207 pages
...possible. The same problem admits of the following geometrical solution. Draw any diameter whatever Rr, **and upon it describe a segment of a circle, containing an angle equal to the given angle,** and cutting the ellipse in Q ; draw Qr, QR, and, parallel to these, the diameters Pp, Dd; these will... | |
| Henry Parr Hamilton - Conic sections - 1834 - 207 pages
...proceed to give the geometrical construction. Draw any diameter Rr, meeting the hyperbola in R, r, **and upon it describe a segment of a circle containing an angle equal to the given angle,** and cutting the hyperbola in Q, draw QR, Qr, and, parallel to these, the semi-diameters CP, CD; these... | |
| Sholto Percy - Industrial arts - 1834
...right angles, these two lines shall meet, if they are produced on the side of R and S. Take a line M'N' **and upon it describe a segment of a circle containing an angle** — RMO, the deficiency of SNM and RMN together from two right angles. In this segment draw the line... | |
| |