 | Olinthus Gregory - Plane trigonometry - 1816 - 278 pages
...angles ABC, and BAC, being determined, the distances are found as before. i EXAMPLE II. In order to find the distance between two trees A and B, which could not be directly measured because of a pool which occupied much of the intermediate space, I measured the distance of each of... | |
 | William Galbraith - 1827 - 566 pages
...53° and 79° 12' ; what is its perpendicular breadth ? Ans.— 1Q5.89. EXAMPLE III. In order to find the distance between two trees A and B, which could not be directly measured on account of a pool of water which occupied the intermediate space, I measured the distance of each from a third object... | |
 | Charles Davies - Surveying - 1830 - 318 pages
...remote, 25° 30'. Required the distance between them. Ans. 178.656 feet. Example 2. — In order to find the distance between two trees, A and B, which could not be directly measured because of a pool, which occupied the intermediate space, the distances of a third object C from each... | |
 | William Galbraith - Astronomy - 1834 - 454 pages
...53° and 79° 12' ; what is its perpendicular breadth ? Ans.— 105.89. EXAMPLE III. In order to find the distance between two trees A and B, which could not be directly measured on account of a pool of water which occupied the intermediate space, I measured the distance of each from a third object... | |
 | Olinthus Gregory - Mathematics - 1834 - 484 pages
...of such examples as are most likely to occur. • • s:. • . , •s* EXAMPLE I. In order to find the distance between two trees A and B, which could not be directly measured because of a pool which occupied much of the intermediate space, I measured the distance of each of... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...most remote, 25° 30' : required the distance between them. Ans. 173.656 feet. 5. In order to find the distance between two trees, A and B, which could not be directly measured because of a pool which occupied the intermediate space, the distance of a third point C from each,... | |
 | Charles Davies - Surveying - 1839 - 376 pages
...the most remote 25° 30' : required the distance between them. Ans. 173.650 feet. 2. In order to find the distance between two trees A and B, which could not be directly measured because of a pool which occupied the intermediate space, the distances of a third point C from each... | |
 | Charles Davies - Surveying - 1839 - 376 pages
...the most remote 25° 30' : required the distance between them. Ans. 173.656 feet. 2. In order to find the distance between two trees A and B, which could not be directly measured because of a pool which occupied the intermediate space, the distances of a third point C from each... | |
 | Charles Davies - Navigation - 1841 - 414 pages
...the most remote 25° 30' : required the distance between them. Ans. 173.656 feet. 2. In order to find the distance between two trees A and B, which could not be directly measured because of a pool which occupied the intermediate space, the distances of a third point C from each... | |
 | Uriah Parke - Arithmetic - 1849 - 414 pages
...Algebraic formulas for doing them. Then I took him into Plane Trigonometry. Said I, In order to find the distance between two trees, A and B, which could not be directly measured, because of a pool which occupied the intermediate space, the distance of a third point, C, from each... | |
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... required the distance between the objects. Ans. 173.656 feet. 2. In order to find the distance between two trees, A and B, which could not be directly measured because of a pool which occupied the intermediate space, the distances of a third point... 
