# Framed Structures and Girders: Theory and Practice. Volume I, Stresses, | ...

McGraw-Hill Book Company, 1911 - Girders - 540 pages

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Page 450 - To provide for wind strains and vibrations from high-speed trains, the top lateral bracing in deck bridges, and the bottom lateral bracing in through bridges, shall be proportioned to resist a lateral force of 600 pounds for each foot of the span ; 450 pounds of this to be treated as a moving load, and as acting on a train of cars, at a line 6 feet above base of rail.
Page 254 - ... the algebraic sum of the vertical components of the stresses in the chord members that meet the vertical at the other end.
Page 11 - The moment of a force about a point is the product of the magnitude of the force by the perpendicular distance from the point to the line of action of the force.
Page 483 - Ibs. per sq. ft. on the same surface plus 400 lbs. per linear ft. of structure applied 7 ft. above the rail for assumed wind force on train, when the structure is either fully loaded or loaded on either track with empty cars assumed to weigh 1,200 Ibs. per linear ft., whichever gives the larger stress.
Page 175 - Center, except the hip vertical, is equal to the vertical component of the stress in the diagonal in the panel to the right, plus the load at the joint of the unloaded chord.
Page 7 - BC is the distance through which the body has moved in the direction of the force, so that the work done in the given time is measured by F x BC.
Page 49 - ... —1,600 foot-pounds at point B. From point B to the right, positive area of the shear diagram is added until at the point C the moment becomes...
Page 43 - To find the moment at any point, remember that the bending moment is the algebraic sum of the moments of the forces to the left of the section under consideration and that moment is the value of force times distance.
Page 7 - The work done by a force upon a body is measured by the product of the force and the distance through which the body moves in the direction of the force.
Page 44 - ... =1,000 pounds, and the load per foot including weight of the beam is 200 pounds. The forces acting on the beam to the left of the first section, two feet from the left end, are the left reaction (1,000 pounds) and the load (including weight) on the part of the beam to the left of the section (400 pounds). The arm of the reaction is 2 feet and that of the 400-pound force is 1 foot (the distance from the middle of the 400-pound load to the section). Hence M2= + 1,000 X 2-400 X 1= + 1,600 foot-pounds.