... be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA, as CE to EA. Join BE, CD ; Then the triangle BDE is equal to the triangle CDE*, * «.i. Books 3-9 - Page 212by Euclid, Sir Thomas Little Heath, Johan Ludvig Heiberg - 1908Full view - About this book
| John Playfair - Trigonometry - 1806 - 311 pages
...which joins the points of section will bt parallel to the remaining side of the triangle. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** ; BD is to DA, as CE to EA. Book VI. Join BE, CD ; then the triangle BDE is equal to the triangle CDEa.... | |
| Euclid - Geometry - 1810 - 518 pages
...which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC:** BD is to DA, as CF. to E A. Ioin BE, CD; then the triangle BDE is equal to the triangle CD E*, because... | |
| Euclides - Geometry - 1816 - 528 pages
...which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** : BD is to DA, as CE to EA. - Join BE, CD; then the triangle BDE is equal to the triangle CDEa, because... | |
| John Playfair - 1819 - 317 pages
...which joins the points of section will be parallel to the remaining side of the triangle. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** : BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (37. 1.),... | |
| Anthony Nesbit, W. Little - Gaging - 1822 - 533 pages
...that semicircle, is a right angle. (Euc. ///. 31. Simp. III. 13. Em. VI. 14.J THEOREM X. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC;** then BD is to DA, as CE to EA, ( Euc, VI. 2, Simp. IV. 12. Em. II. 12.} :i the preceding figure, DE... | |
| Anthony Nesbit - Measurement - 1824 - 434 pages
...that semicircle, is a right angle. (Euc. III. 31. Simp. III. 13. Em. vI. 14.; B THEOREM X. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** ; then BD is to DA, as CE to EA. (Euc. vI. 2. Simp. IV. 12. Em. II. 12J DB THEOREM XI. In the preceding... | |
| Peter Nicholson - Mathematics - 1825 - 372 pages
...tvhich joins ¡he points of section shall be parallel to the remaining tide of the triangle. Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** : BD is to DA, as CE to EA. Join BE, CD; then the triangle RUH U equal to the triangle CDE, (87.) because... | |
| Euclid, Phillips - 1826 - 180 pages
...вс, and through D draw DF parallel to вс. And because FD is drawn parallel to one of the sides вс **of the triangle ABC ; therefore, proportionally as CD is to DA so is BF to FA."** But CD is double of DA ; therefore / \K • 4. 6. also BF is double of FA ; hence BA is triple of AF.... | |
| Robert Simson - Trigonometry - 1827 - 513 pages
...points of section shall be parallel to the remaining side of the triangle. a \ •-, " • Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** : BD shall be to DA, as CE to EA. * 37. 1. Join BE, CD ; then the triangle BDE is equal* to the triangle... | |
| Euclid, Robert Simson - Geometry - 1835 - 513 pages
...which joins the points of section will be parallel to the remaining side of the triangle. • Let DE be **drawn parallel to BC, one of the sides of the triangle ABC** ; then BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE a,... | |
| |