| Paul Deighan - Arithmetic - 1804
...refult will be the whole produft together. Cafe 3d. When both faftors are compound quantities. Rule. **Multiply every term of the multiplicand by every term of the multiplier, and** add the produces together. Nete.* Like figns produce -f, and unlike figns — fXAMPLES. i. Multiply... | |
| Augustus De Morgan - Algebra - 1837 - 248 pages
...the preceding instances, it appears that the rule of multiplication is as follows : Consider the fast **terms as having the sign + ; multiply every term of...preceding rule. a + b — 2c d — a — c from d ad + bd** — 2cd"| from a •••• — aa — ab + 2ac ^Product required, from c — ac — bc + 2cc) Where... | |
| Augustus De Morgan - 1837
...2cc {Subtract from d times arf+5rf+2ac + 2cc— 2crf ditto which gives — aa — ac — ab — be **2. From looking at the preceding instances, it appears...multiplicand by every term of the multiplier, and put** -f- before the products of terms which have the same sign, and — before the products of terms which... | |
| William Scott - Algebra - 1844 - 500 pages
...polynomials composed of any number of terms. Whence, to find the product of two polynomial factors, Kule. **Multiply every term of the multiplicand by every term of the multiplier, and** make reduction of the similar terms. a. In forming the product of two polynomial factors, the partial... | |
| Horatio Nelson Robinson - Algebra - 1850 - 240 pages
...325z2y— 75iz2. CASE 3 . When both the factors are compound quantities, we have the following E n LE . — **MULTIPLY every term of the multiplicand by every term of the multiplier,** separately ; setting down the products one after or under another, with their proper signs ; and add... | |
| Thomas Kimber - 1865
...best removed by working examples with numbers, as (13 + 6) x (7 — 4). Hence the following rule : **Multiply every term of the multiplicand by every term of the multiplier,** remembering to place + before products of quantities with like signs, and — before products of quantities... | |
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