## Key to the Complete System of Mensuration of Superfices and Solids: Containing Solutions to All the Problems and Questions Therein Contained : Calculated for the Use of Schools, Academies, and Private Learners |

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### Common terms and phrases

12 chains 12 rods 144 the square 40 chains 400 the square 576 the square 625 the square acres area required chains half chains the area chains the diameter chains the length chains the longest chains the shortest chains the square corresponding area cube cubic feet cubic inches diagonal diameter required EXAMPLES feet 6 inches feet half feet the area feet the length frustrum greater abscissa half chord half sum half the arc half the base half the chord half the difference half the perimeter hypotenuse inches the solidity less segment longest side ordinate perches PROBLEM IV PROBLEM VII quired rods half rods the area rods the square rods the sum roods semi-conjugate shorter side side required solid feet solidity required square chains square feet square inches square of half square rods square root square yards tabular area tabular versed sine transverse triangle twice the area vertical angle

### Popular passages

Page 40 - All circles are in proportion to each other as the squares of their diameters ; therefore...

Page 51 - To the product of the transverse and abscissa add f of the square of the abscissa, and multiply the square root of the sum by 21.

Page 98 - To the square of the head diameter, add the square of the diameter at the surface of the liquor, and the square of twice the diameter midway between the surface of the liquor and the upper head, and divide the sum by 6 ; the quotient, multiplied by the distance from the surface of the liquor to the upper head, multiplied by .0034, will give the ullage in wine gallons. EXAMPLE. — The diameters are...