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acres algebraic quantities algebraic sum arrange the similar binomial factors bought cistern coefficients common denominator common multiple common term Complete Divisor cube divided dividend division equal factors equivalent fraction Expand a2 exponent Extract the square Factor the following Find the L. C. M. Find the numbers Find the square Find the sum Find the value following equations greater number horse indicates integer LEAST COMMON MULTIPLE less equals less number literal quantities Minuend mixed quantity monomial multiplicand negative quantity nomial Note number of bushels number of hours number of pounds number value Observe parenthesis partial product places of figures polynomial positive quantity prime factors problem quotient Reduce remainder root sought second member second term signs similar fractions similar terms simplest form Simplify Solution square root Subtrahend Suggestion Theorem trial divisor trinomial product twice unknown quantities unlike terms vinculum worth xy xy yards
Page 123 - His head weighed as much as his tail and half his body, and his body weighed as much as his head and tail together.
Page 26 - L ft. 75. A can do a piece of work in 3 days, B can do 3 times as much in 8 days, and C 5 times as much in 12 days ; in what time can they all do the first piece of work ? Ans.
Page 59 - ... digit is added to the number, the order of the digits will be -reversed. What is the number? 59. Twice the units...
Page 114 - ... divisor. Multiply the complete divisor by the figure of the root last found, and subtract the result from the remainder; Proceed in like manner till all the periods of figures have been used.
Page 89 - When the given radical is in a fractional form, it will often be convenient, before applying the rule, to multiply both terms of the fraction by such a quantity as will make the denominator a perfect power of the degree indicated.
Page 51 - If necessary, multiply the given equations by such numbers as will make the coefficients of one of the unknown quantities in the resulting equations of equal absolute value.
Page 46 - But since the second term of the quotient is found by dividing the first term of the second...
Page 123 - ... dollars. How many days did he work, and how many days was he idle ? Ans.
Page 57 - ... Exercises were not restricted to simple easy numbers and problems which may have had a close bearing on the contemporary scene were frequently unreal. This was the era of the cistern problem: If pipe A can fill a cistern in 3 hours and pipe B can fill it in 5 hours and if pipe C will drain the cistern in 6 hours, how long will it take to fill the cistern if all three pipes are operating to capacity? In the late nineteen hundreds, educational psychology became important to school people and by...