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amount annuity annum answer arithmetical assumed root Avoirdupois Balance broadcloth bushels Cash circle circumference common difference compound interest cost cube root cubick currency cyphers Day Book debt decimal denominator diameter discount ditto divide the product dividend divisor dollars Dominical Letter endorsement Epact equal Examples extract farthings federal money feet figure foot fourth frustum gain gallons geometrical Geometrical Progression given number gold greatest term half Hence inches last term Leger length livres Livres Tournois method miles moidores months multiplicand Multiply number of terms paid payment pence perpendicular pound sterling pounds present worth principal Prob Problem proportion quantity quotient rate per cent Reduce remainder repetend Rule shillings side Simple Interest solid specifick gravity square root sterling subtract Suppose surd Table terms less Theorem third velocity vulgar fraction weight whole number yard
Page 199 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 197 - RULE. 1. Separate the given number into periods of three figures each, by putting a point over the unit figure and every third figure beyond the place of units. 2. Find the greatest cube in the left hand period, and put its root in the quotient. 3.
Page 275 - The present worth of any sum, due some time hence, is such a sum, as, if put to interest, would in that time, and at the rate per cent. for which the discount is to be made, amount to the sum or debt then due.
Page 221 - PROBLEM II. The first term, the last term, and the number of terms given, to find the common difference. RULE. — Divide the difference of the extremes by the number of terms less 1 , and the quotient will be the common diffcrenct.
Page 78 - Multiply all the numerators together for a new numerator, and all the denominators for a new denominator; and they will form the fraction required.
Page 372 - A hare starts 12 rods before a hound ; but is not perceived by him till she has been up 45 seconds ; she scuds away at the rate of 10 miles an hour ; and the dog, on view, makes after her at the rate of 16 miles an hour ; how long will the course hold, and what space will be run over, from the spot where the dog started ? Ans.
Page 383 - As the distance between the body to be raised, or balanced, and the fulcrum, or prop, is to the distance between the prop and the point where the power is applied, so is the power to the weight which it will balance.
Page 84 - To reduce any given quantity to the fraction of any greater denomination of the same kind. RULE. — Reduce the given quantity to the lowest term mentioned for a.