| Robert Patterson - Arithmetic - 1819 - 156 pages
...we have the equation ad = be, and this divided by a, will give d = —. In words — multiply the a **second and third terms together, and divide the product by the first,** and the quotient will be the fourth, or term required. II. IN ALLIGATION ALTERNATE. Let a, A, = the... | |
| Jacob Willetts - Arithmetic - 1822 - 191 pages
...DIRECT PROPORTION. RULE. Prepare the given terms, if necessary, and state them as ia whole numbers : **multiply the second and third terms together, and divide the product by the first** : Or, Invert the first term and multiply the three together, as in Multiplication. EXAMPLES. i . If... | |
| Zachariah Jess, Charles Hutton - Arithmetic - 1824 - 210 pages
...dols. ' A " 5 ' 3 : 6 :: 9 : 1 8 more requiring more I 20 : 40 :: 3 : 10 less requiring less RULE. **Multiply the second and third terms together, and divide the product by the first** ; the quotient will be the fourth term, or answer ; in the same name with the second. PROOF. Invert... | |
| Arithmetic - 1824 - 198 pages
...THREE, IN VULGAR FRACTIONS. Prepare the given terms, if necessary, and state them as in whole numbers ; **multiply the second and third terms together, and divide the product by the first.** Or, Invert the dividing term, and multiply the three terms together, as in Multiplication. EXAMPLES.... | |
| Thomas Tucker Smiley - Arithmetic - 1825 - 180 pages
...second terms to the same denomination, and to the lowest denomination mentioned in either oi them. **3. Multiply the second and third terms together, and divide the product by the first** term; the result will be-tbe fourth term OF answer in the same denomination to which the third term... | |
| Zadock Thompson - Arithmetic - 1826 - 164 pages
...less, write the less of the other two given numbers for the third term, and the greater for the first. **3. Multiply the second and third terms together, and divide the product by the first,** the quotient will be the answer. * Proportion is of two kinds ; one arises from considering the differences... | |
| Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 200 pages
...kind, the first term ; and that which is of the same name or kind with the answer, the second term. 2. **Multiply the second and third terms together, and divide the product by the first** term, and the quotient will be the fourth term, or answer. The notes under the general rule are applicable... | |
| Poplar House Academy, London, J & S. - 1826 - 92 pages
...necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then, **multiply the second and third terms together, and divide the product by the first,** and the quotient will be the answer, in the same denomination that the third term was reduced to ;... | |
| Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
| Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first... | |
| |