| John Budge - Mining engineering - 1845 - 218 pages
...SHROUD-LAID* ROPE. RULE — State the question as in direct proportion, square the first and third terms, **multiply the second and third terms together, and divide the product by the first.** EXAMPLE. How many standard yarns, or threads, are there in a 14-inch capstan rope ? in. yarns. in.... | |
| Frederick Emerson - 1846
...than the third, make the less of the two remaining terms the second term, and the greater the first. **Multiply the second, and third terms together, and divide the product by the first** term: the quotient will be the fourth term, or answer. If there are different denominations in the... | |
| George Roberts Perkins - Arithmetic - 1846 - 258 pages
...written the three terms of the proportion, or, at usually expressed, having stated the question, then **multiply the second and third terms together, and divide the product by** <AŤ first term. :!:NoTE. — Since there is a ratio between the first and cond terms, they must be... | |
| William Vogdes - Arithmetic - 1847 - 256 pages
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. **Multiply the second and third terms together, and divide the product by the first;** the quotient will be the answer to the question in the same denomination as the third term. 3. If either... | |
| William B. Young - Arithmetic - 1848 - 297 pages
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen **multiply the second and third Terms together, and divide the product by the first** Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term... | |
| Isaiah Steen - 1848
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, **multiply the second and third terms together, and divide the product by the first** term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination... | |
| rev. Frederick Calder - 1848
...and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then **multiply the second and third terms together, and divide the product by the first:** the quotient will be the answer or fourth term, expressed in the same denomination as that in which... | |
| Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 249 pages
...name or kind with the answer. tion, 'and reduce the middle term to the lowest name mentioned in it. **3. Multiply the second . and third terms together, and divide the product. by the first** term ; the quotient will be the answer in the same denomination you left the middleterm in ; which... | |
| J. M. Scribner - Mechanical engineering - 1849 - 264 pages
...of the two remaining numbers for the second term, and the greater for the first ; and in either case **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination as the third term. NOTE. — If the first... | |
| Charles Guilford Burnham - 1850
...expresses the demand, for the first, and the remaining term of the condition for the second term. II. **Multiply the second and third terms together, and divide the product by the first.** III. If the first or second terms consist of different denominations, reduce both to the lowest mentioned.... | |
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