Multiply the complete divisor by the second figure of the root, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. New Practical Arithmetic - Page 363by Eugene L. Dubbs - 1901 - 440 pagesFull view - About this book
| Joseph Ray - Algebra - 1857 - 408 pages
...the root and also on the right of the divisor. 4th. Multiply the divisor thus increased by the last figure of the root; subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. 5th. Double the whole root already found for a new divisor,... | |
| Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...the trial divisor, and add it to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period for a new dividend. To the last true divisor and the number immediately... | |
| Dana Pond Colburn - 1858 - 288 pages
...7th. Multiply the true divisor by the last root figure, placing the product under the dividend. 8th. Subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 9th. Add together the square of the last quotient^figure, the last true divisor, and... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 456 pages
...trial divisor, and add it to the saute fur a true divisor. j\fullij>l// the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring domi the next period for a new dividend. To the last true divisor and the number immediate!;/... | |
| Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...the trial divisor, and add it to the same for a true divisor. Multiply the true divisor by the last figure of the root : subtract the product from the dividend, and to the remainder bring down the next period far a new dividend. To the last true divisor and the number immediately... | |
| Elias Loomis - Algebra - 1858 - 394 pages
...annex the result both to the root and the divisor. 4. Multiply the divisor thus increased by the last figure of the root ; subtract the product from the dividend, and to the remaindei bring down the next period for a new dividend. 5. Double the whole root now found for a new... | |
| Chambers W. and R., ltd - 1859 - 344 pages
...sums together, and their amount is the complete divisor. 4. Multiply the complete divisor by the last figure of the root ; subtract the product from the dividend; and to any remainder, annex the next period of three figures, to form a new dividend. 5. Form a new DIVISOR... | |
| James B. Dodd - Arithmetic - 1859 - 368 pages
...multiplying the result by the last figure. 5. Multiply the completed divisor by the last figure in the root; subtract the product from the dividend ; and to the remainder affix the next period, for a new dividend. 6. Find the next incomplete divisor by adding to the last... | |
| James B. Dodd - Algebra - 1859 - 368 pages
...multiplying the result by the last figure. 5. Multiply the completed divisor by the last figure in the root ; subtract the product from the dividend ; and to the remainder affix the next period for a new dividend. 6. Find the next incomplete divisor by adding to the last... | |
| Dana Pond Colburn - Arithmetic - 1860 - 388 pages
...Multiply tlie true divisor by the last root figure, placing the product under the dividend. Eighth. Subtract the product from the dividend, and to the remainder annex the next period for a new dividend. Ninth. Add the square of the last quotient figure to the last true divisor and the... | |
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