| James Hann - 1849
...disjunct. This practical method will be useful to seamen, and requires very little effort of memory. **The sine of the middle part, is equal to the product of the** cosines of the extremes disjunct. From these two equations, proportions may be formed, observing always... | |
| William Chauvenet - 1852
...: I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. The correctness of these rules will be shown by taking each of the five... | |
| Elias Loomis - Trigonometry - 1855 - 178 pages
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and **the sine of the middle part, is equal to the product of the tangents of the** adjacent parts, or to the product of the cosines of the opposite parts. It will assist the learner... | |
| GEORGE R. PERKINS - 1856
...RULES, I. The sine of the middle part is equal to the product of the tangents of the adjacent parts. II. **The sine of the middle part is equal to the product of the** cosines of the opposite parts. If now we take in turn each of the five parts as the middle part, and... | |
| Henry William Jeans - 1858
...of the middle part is equal to the product of the tangents of the two parts adjacent to it. EULE B. **The sine of the middle part is equal to the product of the** cosines of the two parts opposite to, or separated from it. Having written down the equation according... | |
| ELIAS LOOMIS, LL.D. - 1859
...part required may then be found by the following RULE OF NAPIER. (211.) The product of the radius and **the sine of the middle part, is equal to the product of the tangents of the** adjacent parts, or to the product of the cosines of the opposite parts. It will assist the learner... | |
| John Daniel Runkle - Mathematics - 1859
...NAPIER'S RULES. BY TUI MAN HENRY 8AFFORD. IN the form in which they are usually given, the rules are — **I. The sine of the middle part is equal to the product of** tlie tangents of tJie adjacent parts. II. T/te sine of the middle part is equal to tJic product of... | |
| 1860
...RULE I. The sine of the middle pari equals the product of the cosines of the opposite parts. RULE II. **The sine of the middle part is equal to the product of the tangents of the** adjacent parts. That the second of these rules may be deduced from the first has been shown by Mr.... | |
| John Daniel Runkle - Mathematics - 1860
...RULE I. The sine of the middle part equals the product of the cosines of the opposite parts, RULE II. **The sine of the middle part is equal to the product of the tangents of the** adjacent parts. It must be remembered that, instead of the hypothenuse and the two acute angles, their... | |
| Horatio Nelson Robinson - Geometry - 1860 - 453 pages
...of the middle part is equal to the product of the tangents of the adjacent parts. 2. The radius into **the sine of the middle part is equal to the product of the** cosines of the opposite parts. These rules are known as .Napier's Rules, because they were first given... | |
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