| James Bates Thomson - Arithmetic - 1846 - 376 pages
...second term, and the other for the first. III. Finally, multiplying the second and third terms together, **divide the product by the first, and the quotient will be the** answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer... | |
| James Bates Thomson - Arithmetic - 1846 - 348 pages
...second term, and the other for the first. IIL Finally, multiplying the second and third terms togethf-r, **divide the product by the first, and the quotient will be the.** answer in the same denomination as the third term. PROOF. — Multiply the first term ami the ansmr... | |
| George Roberts Perkins - Arithmetic - 1846 - 258 pages
...written the three terms of the proportion, or, at usually expressed, having stated the question, then **multiply the second and third terms together, and divide the product by** <AŤ first term. :!:NoTE. — Since there is a ratio between the first and cond terms, they must be... | |
| William Vogdes - Arithmetic - 1847 - 256 pages
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. **Multiply the second and third terms together, and divide the product by the first;** the quotient will be the answer to the question in the same denomination as the third term. 3. If either... | |
| Roswell Park - Best books - 1847 - 580 pages
...first. The question being thus stated, multiply the second and third terms together, and divide their **product by the first; and the quotient will be the fourth term,** or answer sought. A Compound Proportion, including the solution of problems by what is called the Double... | |
| James Bates Thomson - Arithmetic - 1847 - 422 pages
...second term, and the other for the first. III. finally, multiply the second and third terms together, **divide the product by the first, and the quotient will be the** answer in the same denomination as the third term. PROOF. — Multiply the first term and the answer... | |
| Isaiah Steen - 1848
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, **multiply the second and third terms together, and divide the product by the first** term; the quotient is the answer, or fourth proportional required; and it is always of the same denomination... | |
| William B. Young - Ready-reckoners - 1848 - 274 pages
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen **multiply the second and third Terms together, and divide the product by the first** Term, the result will be the fourth Term or answer, in the same de nomination to which the third Term... | |
| rev. Frederick Calder - 1848
...and if the third term consist of several denominations, reduce it to the lowest name mentioned. Then **multiply the second and third terms together, and divide the product by the first:** the quotient will be the answer or fourth term, expressed in the same denomination as that in which... | |
| James Bates Thomson - Arithmetic - 1848 - 422 pages
...second term, and the other for the first. III. Finally, multiply the second and third terms together, **divide the product by the first, and the quotient will be the** answer in the tame denomination as the third term. PROOF. — Multiply the first term and the answer... | |
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