| Great Britain. Education Department. Department of Science and Art - 1882
...the ratio of AN to NB is the duplicate of the ratio of AM to MB. 2. If two triangles of equal area **have an angle of the one equal to an angle of the other,** prove that the sides about the equal angles are reciprocally proportional. 3. Shew how to divide a... | |
| Mathematical association - 1883
...two adjoining sides of the one respectively equal to two adjoining sides of the other, and likewise **an angle of the one equal to an angle of the other;** the parallelograms are identically equal. [By Superposition.] COR. Two rectangles are equal, if two... | |
| Evan Wilhelm Evans - Geometry - 1884 - 155 pages
...AO parallel to BC. M ANC = ACN = CAO. ANC = CBA + BAN. Complete the proof. 24. Two triangles which **have an angle of the one equal to an angle of the other,** are to each other as the products of the sides in- B eluding the equal angles. See Theo. VII. BAC :... | |
| Evan Wilhelm Evans - Geometry - 1884 - 155 pages
...; hence, it is also similar to DFE. Therefore, two triangles, etc. THEOREM XI. Two triangles having **an angle of the one equal to an angle of the other, and** the sides about those angles proportional, are similar. Let the two triangles ABC, DEF, have the angle... | |
| Mathematical association - 1884
...two adjoining: sides of the one respectively equal to two adjoining sides of the other, and likewise **an ang:le of the one equal to an angle of the other** ; the parallelograms are identically equal. Let ABCD, EFGH be two parallelograms having the angle ABC... | |
| William Kingdon Clifford - Mathematics - 1885 - 271 pages
...proposition about parallel lines.1 The first of these deductions will now show us that if two triangles **have an angle of the one equal to an angle of the other and** the sides containing these angles respectively equal, they must be equal in all particulars. For if... | |
| Lewis Carroll - Geometry - 1885 - 275 pages
...have two adjacent sides of the one respectively equal to two adjacent sides of the other, and likewise **an angle of the one equal to an angle of the other** ; the Parallelograms are identically equal.' This might be a useful exercise to set ; but really it... | |
| W. E. BYERLY - 1887
...B'C' A'B" hence AD BC A'D' X B'C' and we have ABC A' B' C' EXERCISE. Theorem. — Two triangles having **an angle of the one equal to an angle of the other** are to each other as the products of the sides including the equal angles. Suggestion. Let ADE and... | |
| Dalhousie University - 1888
...sides, the solids contained by the alternate segments of these lines are equal. 3. If two triangles **have an angle of the one equal to an angle of the other, and** have their areas proportional to the squares of the side* opposite these equal angles, they must be... | |
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