| Daniel Adams - Arithmetic - 1828 - 266 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
| Daniel Adams - Arithmetic - 1828 - 286 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first... | |
| Thomas Tucker Smiley - 1830 - 188 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. Multiply the second and third terms together, and divide the product by the .first term ; the result will be the fourth term, or answer, in the same denomination to which the third term was reduced.... | |
| Daniel Adams - Arithmetic - 1830 - 294 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Daniel Adams - Arithmetic - 1830 - 280 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Arithmetic - 1831 - 198 pages
...are; and if the third term consist of several denominations, reduce it to its lowest denomination; then, Multiply the second and third terms together,...product by the first term: the quotient will be the answer. Note. — The product of the second and third termsis of the same denomination as the third... | |
| Daniel Adams - Arithmetic - 1831 - 276 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, which will always be of the same denomination cs the third term. Note 1. If the first... | |
| Thomas Conkling (W.) - Arithmetic - 1831 - 302 pages
...before taught; then, state the question as directed in whole numbers, p. 109; and, as in that rule, multiply the second and third terms together, and divide the product by the first; that is, multiply the denominator of the first term by the numerators of the 2d and 3d, for a new numerator;... | |
| Robert Gibson - Surveying - 1832 - 290 pages
...may be as much greater or less than the third as the second term is greater or less than the first, then multiply the second and third terms together, and divide the product by the first term, and the quotient will be the answer ; — in the same denomination with the third term. EXAMPLES. If... | |
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