| Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first... | |
| Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
| Thomas Tucker Smiley - 1830 - 180 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. **Multiply the second and third terms together, and divide the product by the .first term ; the** result will be the fourth term, or answer, in the same denomination to which the third term was reduced.... | |
| Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Arithmetic - 1831 - 198 pages
...are; and if the third term consist of several denominations, reduce it to its lowest denomination; **then, Multiply the second and third terms together,...product by the first term: the quotient will be the** answer. Note. — The product of the second and third termsis of the same denomination as the third... | |
| Daniel Adams - Arithmetic - 1831 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination cs the third term. Note 1. If the first... | |
| Thomas Conkling (W.) - Arithmetic - 1831 - 275 pages
...before taught; then, state the question as directed in whole numbers, p. 109; and, as in that rule, **multiply the second and third terms together, and divide the product by the first;** that is, multiply the denominator of the first term by the numerators of the 2d and 3d, for a new numerator;... | |
| Robert Gibson - Surveying - 1832 - 248 pages
...may be as much greater or less than the third as the second term is greater or less than the first, **then multiply the second and third terms together, and divide the product by the first term,** and the quotient will be the answer ; — in the same denomination with the third term. EXAMPLES. If... | |
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