| Charles Davies - Arithmetic - 1846 - 340 pages
...it is less place the greater there. IV. Then multiply the second and third terms together and Ans. **divide the product by the first term: the quotient will be the** fourth term or answer sought, and will be of the same denomination as the third term. Ex. 3. If 48... | |
| Oliver Welch - 1847
...denomination; and reduce the middle number, or term, into the lowest denomination mentioned; then (7) **multiply the second and third terms together, and divide the product by the first;** the quotient will be (°) the answer, or fourth term sought; and always will be (a) of the same denomination... | |
| William Vogdes - Arithmetic - 1847 - 256 pages
...the first and second terms to the same denomination, and the third to the lowest name mentioned. 2. **Multiply the second and third terms together, and divide the product by the first;** the quotient will be the answer to the question in the same denomination as the third term. 3. If either... | |
| Isaiah Steen - 1848
...that place. Then, the first two terms being reduced to the same simple denomination, when necessary, **multiply the second and third terms together, and divide the product by the first term; the quotient** is the answer, or fourth proportional required; and it is always of the same denomination as the last... | |
| William B. Young - Ready-reckoners - 1848 - 274 pages
...second Terms to the same Jenomination, and to the lowest denomination mentioned in either of them@ ihen **multiply the second and third Terms together, and divide the product by the first Term, the** result will be the fourth Term or answer, in the same de nomination to which the third Term was reduced,... | |
| rev. Frederick Calder - 1848
...so : and if the third term consist of several denominations, reduce it to the lowest name mentioned. **Then multiply the second and third terms together, and divide the product by the first:** the quotient will be the answer or fourth term, expressed in the same denomination as that in which... | |
| Nathan Daboll, David Austin Daboll - Arithmetic - 1849 - 249 pages
...term, place the least of the two remaining numbers fqr the second term, and the greater for the first **term ; then multiply' the second and third terms together, and divide the -product by the first term,** and the quotient will be the answer in the same name "of the third term EXAMPLES. 1. If 6 yards cost... | |
| J. M. Scribner - Mechanical engineering - 1849 - 264 pages
...of the two remaining numbers for the second term, and the greater for the first ; and in either case **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination as the third term. NOTE. — If the first... | |
| George Roberts Perkins - Arithmetic - 1849 - 347 pages
...Having written the three terms of the proportion, or, as usually expressed, having stated the question, **then multiply the second and third terms together, and divide the product** L,j the first term. NOTE. — Since there is a ratio between the first and second terms, they must... | |
| George Roberts Perkins - Arithmetic - 1850 - 347 pages
...Having written the three terms of the proportion, or, as usually expressed, having stated the question, **then multiply the second and third terms together, and divide the product by the first term.** NOTE. — Since there is a ratio between the firsthand second terms, they must be reduced to the same... | |
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